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2 years ago

10 +4m when m = -2 i really need help on this lol

Mathematics

2 answers:

Levart [38]2 years ago

6 0

10 + (4 x -2)
=2
10 + -8 = 2

Leviafan [203]2 years ago

5 0

<h2><u>ANSWER</u></h2>

Step-by-step explanation:

10+4m

=> 10+4(-2)

=> 10-8

=> 2

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Ahhhh help everyone help me solve this ....

vovangra [49]

Answer:

$y = \frac{18 {w}^{2} {x}^{2} {z}^{2} }{25}$

Step-by-step explanation:

$\frac{3wx}{ \sqrt{2y} } = \frac{5}{2z} \\ \\ \sqrt{2y} \times 5 = 3wx \times 2z \\ \\ \sqrt{2y} \times 5 = 6wxz \\ \\ \sqrt{2y} = \frac{6wxz}{5} \\ \\ {( \sqrt{2y} })^{2} = {( \frac{6wxz}{5} })^{2} \\ \\ 2y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \div 2 \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \times \frac{1}{2} \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{50} \\ \\ \\ y = \frac{18 {w}^{2} {x}^{2} {z}^{2} }{25}$

I hope I helped you^_^

4 0

2 years ago

Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)

Fantom [35]

Answer:

Given: $\sin(x) = (4/5)$ .

Assuming that $0 < x < 90^{\circ}$ , $\cos(x) = (3/5)$ while $\tan(x) = (4/3)$ .

Step-by-step explanation:

By the Pythagorean identity $\sin^{2}(x) + \cos^{2}(x) = 1$ .

Assuming that $0 < x < 90^{\circ}$ , $0 < \cos(x) < 1$ .

Rearrange the Pythagorean identity to find an expression for $\cos(x)$ .

$\cos^{2}(x) = 1 - \sin^{2}(x)$ .

Given that $0 < \cos(x) < 1$ :

$\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}$ .

Hence, $\tan(x)$ would be:

$\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}$ .

7 0

2 years ago

Jerome deposits $4,700 in a certificate of deposit that pays 6 1/2% interest, compounded annually. How much interest does Jerome

Inessa05 [86]

Answer:

$305.5

Step-by-step explanation:

7 0

2 years ago

PLEASE HELP

LekaFEV [45]

Answer: one solution

Step-by-step explanation:

CONCEPT:

- One solution is when the final variable would be able to find a solution.

- Infinite solution is when the equations result in 0=0, meaning any number will fit

- No solution is when the equation results in both sides on equal.

SOLVE:

Given

3/4x-7=3(1/6x+1)

Expand Parenthesis

3/4x-7=1/2+3

Multiply both sides by the LCM of fractions (Least Common Multiple)

4(3/4x-7)=4(1/2x+3)

3x-28=2x+12

Subtract both sides by 2x

3x-28-2x=2x+12-2x

x-28=12

Add both sides by 28

x-28+28=12+28

x=40

Since we are able to get exactly one solution, there is only one solution.

Hope this helps!! :)

Please let me know if you have any quesionts

5 0

2 years ago

How do I simplify 1/-5z^-5?

belka [17]

$\bf \cfrac{1}{-5z^{-5}}\\\\
-------------------------\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\\ \quad \\
% negative exponential denominator
a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 
\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}} \\\\
-------------------------\\\\
thus
$

$\bf -\cfrac{1}{5}\cdot \cfrac{1}{z^{-5}}\implies -\cfrac{1}{5}\cdot \cfrac{1}{\frac{1}{z^5}}\implies -\cfrac{1}{5}\cdot \cfrac{\frac{1}{1}}{\frac{1}{z^5}}\implies -
\cfrac{1}{5}\cdot \cfrac{1}{1}\cdot \cfrac{z^5}{1}
\\\\\\
-\cfrac{z^5}{5}$

3 0

2 years ago