Answer:
def typeHistogram(it,n):
d = dict()
for i in it:
n -=1
if n>=0:
if str(type(i).__name__) not in d.keys():
d.setdefault(type(i).__name__,1)
else:
d[str(type(i).__name__)] += 1
else:
break
return list(d.items())
it = iter([1,2,'a','b','c',4,5])
print(typeHistogram(it,7))
Explanation:
- Create a typeHistogram function that has 2 parameters namely "it" and "n" where "it" is an iterator used to represent a sequence of values of different types while "n" is the total number of elements in the sequence.
- Initialize an empty dictionary and loop through the iterator "it".
- Check if n is greater than 0 and current string is not present in the dictionary, then set default type as 1 otherwise increment by 1.
- At the end return the list of items.
- Finally initialize the iterator and display the histogram by calling the typeHistogram.
Answer:
It is any information that is audio or video but not text.
Explanation:
Answer:
class Main {
public static void printPattern( int count, int... arr) {
for (int i : arr) {
for(int j=0; j<count; j++)
System.out.printf("%d ", i);
System.out.println();
}
System.out.println("------------------");
}
public static void main(String args[]) {
printPattern(4, 1,2,4);
printPattern(4, 2,3,4);
printPattern(5, 5,4,3);
}
}
Explanation:
Above is a compact implementation.
