<span>First we have to determine the slope of each lines by transforming to the slope-intercept form:
y=(3x-7/)4; m2= ¾y=(12x+6)/5, m3 = 12/5
The formula to be used in the proceeding steps is a=tan^-1(m1-m2)/1+m1m2=tan^-1(m1-m2)/1+m1m2
substituting, a=tan^-1(m1-3/4)/1+3m1/4=tan^-1(m1-12/5)1+12m1/5) =>(4m1-3)/(4+3m1)=(5m1-12)/(5+12m1)m1 = -1applying this slope
y -y1 = m(x-x1)
when y1 = 5 and x1 = 4 then,
y - 5 = -1(x-4)
y = -x +4+ 5 ; y = -x +9</span>
Y=5/2 should be the answer
The arrangement of the numbers in descending order (largest to smallest) are as follows;
- a). 5.5, 4, 29/33, -3/4, -2.365
- b). 10, 5.855, 5/8, 1/2 -2π, -8
<h3>What is the arrangement of the numbers in descending order in each case?</h3>
It follows from convention that the positive numbers are larger than negative numbers and hence, should appear before negative numbers when the arrangement is in descending order.
Consequently, the numbers can be evaluated and arranged as in the answer above with positive numbers increasing rightwards and negative numbers decreasing leftward of 0 on the number line.
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<u>Step</u><u> </u><u>1</u>
given
<u>Step</u><u> </u><u>2</u>

<u>Step</u><u> </u><u>3</u>

Reason: Reflexive property
<u>Step</u><u> </u><u>4</u>
ASA