The setup boxes in the synthetic division are (b)
<h3>How to determine the setup boxes?</h3>
The dividend is given as:
x^3 + 4x^2 + x - 6
The divisor is given as:
x - 2
Set the divisor to 0
x - 2 = 0
Solve for x
x = 2
Remove the variables in the dividend
1 + 4 + 1 - 6
Remove the arithmetic signs
1 4 1 - 6
So, the setup is:
2 | 1 4 1 - 6
Hence, the setup boxes are (b)
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Answer:
|x - 1 |> 6,
Step-by-step explanation:
First we find the distance between the two points
-5 to 7
7 - -5 =7+5 = 12
We find 1/2 that distance
12/2 = 6
So we are looking for a greater-than inequality because we are looking for the outsides because we want a less than and a greater than
|x - b |> c,
The center is 6 to that is c
|x - b |> 6,
To find the value of b
Let x = 7
7 -b =6
b=1
|x - 1 |> 6,
We can check by using -5
|-5 - 1 |> 6,
Answer:
y= -a*x + 12
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>b</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>b</u>
Step-by-step explanation:
ax+by=12 (subtract "ax" from both sides so that the one on the left will become zero and we will have "by" )
by= -ax+12(divide both side by "by" so that we will have the equation as "y=mx+b")
finally the result will be:
y= -a*x + 12
b b
Answer:
IV
Step-by-step explanation:
The 6 is to the right of the x axis ( positive x) and the -8i is below the x axis to the right.
