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3 years ago

What is the product of –12 and –4? –48 –16 16 48?

Mathematics

2 answers:

Verizon [17]3 years ago

4 0

Answer:

positive 48

Step-by-step explanation:

negative times a negative is positive

Stels [109]3 years ago

3 0

Answer:

The answer is +48

Step-by-step explanation:

a negative times a negative is a positive. Heres a little tip!

Love= Positive

Hate = Negative

if you love to love youre a lover

if you hate to hate youre a lover

if you hate to love youre a hater

if you love to hate youre a hater

hater= negative number

lover= positive number

(this only applies to multiplication and division)

I hope this was helpful. Make sure to rate or mark as brainliest! or to thank. or all. your choice :)

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Read 2 more answers

which shows one way to determine the factors of 12x^3 - 2x^2 + 18x - 3 by grouping? A) 2x^2(6x - 1) + 3(6x - 1) B) 2x^2(6x - 1)

Eva8 [605]

Answer:

$2x^2(6x - 1) + 3(6x - 1)$

Step-by-step explanation:

Given

$12x^3 - 2x^2 + 18x - 3$

Required

Factorize

To start with; we need to group the expression into two

$(12x^3 - 2x^2) + (18x - 3)$

Factorize each grouped expression, using their common factor

$2x^2(6x - 1) + 3(6x - 1)$

From the list of given options;

Option A is correct

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3 years ago

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3 years ago

Write each of the following as a function of theta.<br> 1.) sin(pi/4 - theta) 2.) tan(theta+30°)

Paladinen [302]

Step-by-step explanation:

Let x represent theta.

$\sin( \frac{\pi}{4} - x )$

Using the angle addition trig formula,

$\sin(x - y) = \sin(x) \cos(y) - \cos(x) \sin(y)$

$\sin( \frac{\pi}{4} ) \cos(x) - \cos( \frac{\pi}{4} ) \sin(x)$

$( \frac{ \sqrt{2} }{2}) \cos(x) - (\frac{ \sqrt{2} }{2} )\sin(x)$

Multiply one side at a time

Replace theta with x , the answer is

$\frac{ \sqrt{2} \cos(x) }{2} - \frac{ \sin(x) \sqrt{2} }{2}$

2. Convert 30 degrees into radian

$\frac{30}{1} \times \frac{\pi}{180} = \frac{\pi}{6}$

Using tangent formula,

$\tan(x + y) = \frac{ \tan(x) + \tan(y) }{1 - \tan(x) \tan(y) }$

$\frac{ \tan(x) + \tan( \frac{\pi}{6} ) }{1 - \tan(x) \tan( \frac{\pi}{6} ) }$

Tan if pi/6 is sqr root of 3/3

$\frac{ \tan(x) + ( \frac{ \sqrt{3} }{3} ) }{1 - \tan(x) (\frac{ \sqrt{3} }{3} ) }$

Since my phone about to die if you later simplify that,

you'll get

$\frac{(3 \tan(x) + \sqrt{3} )(3 + \sqrt{3} \tan(x) }{3(3 - \tan {}^{2} (x) }$

Replace theta with X.

4 0

3 years ago