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LenaWriter [7]
2 years ago
5

without dividing explain whether 5 1/6 divided by 3 5?8 is greater or less than 5 1/6 divided by 2 2/5.

Mathematics
1 answer:
Kazeer [188]2 years ago
5 0

Answer:

less

Step-by-step explanation:

without dividing you can still see that you're dividing the number 5 1/6 into more small pieces when you divide by 3 5/8 than when dividing by 2 2/5. it's like how you know that dividing 100 by 3 is going to give you a smaller number than dividing it by 2 because when you divide 100 by 3 the groups will have smaller numbers because there are more groups.

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mote1985 [20]
First we find the area 10 x 21 = 210 then we multiply 210 x .70 and we get 147.00 total cost. d. 147.00
4 0
3 years ago
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Solve for j.<br> 3 + 4<br> 2<br> -3
xeze [42]

Answer:

Hello!

Step-by-step explanation:

How do we solve for j when there is no equation with j in it to solve for j. <em><u>Hope we can help you with this when we get a equation! </u></em>

3 0
3 years ago
X(2x-5)+x(2x-3)=(4x+6)(x-3)
Helga [31]

Answer:

x=9

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How can I solve this?<br>Please use the simplest format​
IgorLugansk [536]

Answer:

option D is true.

Step-by-step explanation:

The right-angled triangle is shown.

From the right-angled triangle,

The angle Ф = 60°

We know that the trigonometric ratio

tan Ф = opposite / adjacent

  • opposite = 4
  • adjacent = n

Thus,

tan 60 = 4 / n

√3 = 4/n

n = 4/√3

Thus,

n = 4/√3

  = (4 × √3) / (√3 × √3)

  = 4√3 / 3

Thus,

n  = 4√3 / 3

Using Pythagorean theorem

m = √n²+4²

m=\sqrt{\left(4\cdot \frac{\sqrt{3}}{3}\right)^2+4^2}

m=\sqrt{\frac{4^2}{3}+4^2}

m=\sqrt{\frac{64}{3}}

m=\frac{8}{\sqrt{3}}

m=\frac{8\sqrt{3}}{3}

Thus,

  • m=\frac{8\sqrt{3}}{3}
  • n  = 4√3 / 3

Therefore, option D is true.

3 0
2 years ago
Help me please. <br>20+(-16)4
Sphinxa [80]
P.E.M.D.A.S
First , you multiply.

200+(-16)4
200+(-64)

Since they have different signs, you subtract and keep the sign of the greater absolute value.

200+(-64)=136
8 0
3 years ago
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