It is in the conditional formatting area that such changes are made.
Answer:
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Answer:
spooler
Explanation:
A print server uses a print spooler as a software holding area for jobs waiting to be printed.
Answer:
Output: yes
Explanation:
First if statement is satisfied, since numA==2, so yes is printed.
The elif statement is skipped altogether, since elif statements are only evaluated, when the statement above if false, which it is not.
Answer:
To do this you'll need to use malloc to assign memory to the pointers used. You'll also need to use free to unassign that memory at the end of the program using the free. Both of these are in stdlib.h.
#include <stdlib.h>
#include <stdio.h>
#define SIZE_X 3
#define SIZE_Y 4
int main(void){
int **matrix, i, j;
// allocate the memory
matrix = (int**)malloc(SIZE_X * sizeof(int*));
for(i = 0; i < SIZE_X; i++){
matrix[i] = (int *)malloc(SIZE_Y * sizeof(int));
}
// assign the values
for(i = 0; i < SIZE_X; i++){
for(j = 0; j < SIZE_Y; j++){
matrix[i][j] = SIZE_Y * i + j + 1;
}
}
// print it out
for(i = 0; i < SIZE_X; i++){
for(j = 0; j < SIZE_X; j++){
printf("%d, %d: %d\n", i, j, matrix[i][j]);
}
}
// free the memory
for(i = 0; i < SIZE_X; i++){
free(matrix[i]);
}
free(matrix);
return 0;
}
