Answer:
BEGIN
INPUT N
IF N>0 AND N<10 THEN
OUTPUT "blue"
ELSE
IF N>10 AND N<20 THEN
OUTPUT "red"
ELSE
IF N>20 AND N<30 THEN
OUTPUT "green"
ELSE
OUTPUT "It is not a correct color option"
ENDIF
END.
Explanation:
Answer:
it's A:state the role each member played in the project
Answer:
5 Ways to Improve Your Coding and Programming Skills
Take advantage of books and other free resources. ...
Sign up for a bootcamp. ...
Practice, practice, practice. ...
Engage with the computer science community. ...
Pursue a formal education in computer science.
Answer:
True
Explanation:
A Domain Name Service comprises of computer servers that carries a database of public IP addresses and their related human-readable domain names/hostnames, it receives query as hostnames and helps to translates those human-readable domain names/hostnames into IP addresses that computers and routers understand.
Answer:
#include <iostream>
#include <string>
#include <stack>
#include <math.h>
using namespace std;
int main() {
string s;
double n=0;
int position=0;
stack<int> wholeNumbers;
cout<<"Enter a decimal number:";
cin>>s;
string::iterator counter = s.begin();
while(*counter!='.' && counter!=s.end()){
wholeNumbers.push(*counter-48);
counter++;
position=position+1;
}
for(int i=0;i<position;i++){
n=n+(wholeNumbers.top()*pow(10,i));
wholeNumbers.pop();
}
position=-1;
if(counter!=s.end()){
counter++;
}
while(counter!=s.end()){
n=n+((*counter-48)*pow(10,position));
position=position-1;
counter++;
}
cout<<n;
}
Explanation:
- Inside the while loop, push the push a number to the wholeNumbers stack by subtracting it with 48.
- Increment the counter and position variable by 1 inside the while loop.
- Count the number of digit, push each digit to top of stack and find the end of the number,
- Run a for loop up to the value of position variable and pop a value from the wholeNumbers stack.
