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jeka57 [31]
3 years ago
13

33. Which of the following energy sources emits carbon dioxide, creating pollution?

Biology
1 answer:
vitfil [10]3 years ago
4 0

I would have to say coal

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drawing upon the results of this exercise, why is pseudomonas aeruginosa of such concern in burn patients chegg
Agata [3.3K]

Pseudomonas aeruginosa is of concern in burn patients beacuse it can cause infections like AIDS,diabetes mellitus , etc.

Pseudomonas aeruginosa is a common bacteria that can be found in soil, water, and other environmental niches. Burn wounds are intricate microenvironments where bacterial pathogens like P. aeruginosa can cause infections. Typical virulence factors like pyocyanin and pyoverdine expressed at higher levels than they would have under conventional laboratory conditions.

Elastase is secreted as well, is primarily responsible for the host tissues'  degradation. P. aeruginosa infections cause severe consequences mostly in organisms with weakened natural defences. Examples of these circumstances include burn wound patients.

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2 years ago
What technology advancement was necessary before scientists could begin to observe cells
Artist 52 [7]
Very powerful microscopes were needed before cells could be observed in detail
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3 years ago
Which of the following represents the codon sequence that
Elden [556K]

Answer:

ATAGTCCTA

Explanation:

a and t pair together and c and g so it would be ATAGTCCTA i think

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3 years ago
The bones in the wings of a bat are similar to the bones in the flipper of the whale. This information suggests that bats and wh
cricket20 [7]
Bone structure!

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4 0
3 years ago
A trait has two alleles represented by p and q if p 0.22 what is q
pav-90 [236]
q=0,78  
To calculate the frequency of the allele we use the Hardy-Weinberg equation. The Hardy-Weinberg equation is used to calculate the genetic variation of a population at equilibrium. If the alleles are A and a, p is the frequency of the allele A and q is the frequency of the allele a. Hardy-Weinberg equation for alleles A and a:
p² + 2pq + q² = 1
p² is the frequency of the homozygous genotype AA, 2pq is the frequency of the heterozygous genotype Aa and q² is the frequency of the homozygous genotype aa.
p²+2pq+q²=(p+q)²=1
p+q=1
<span>If p=0,22 q=1-0,22=0,78</span>
3 0
3 years ago
Read 2 more answers
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