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zaharov [31]
3 years ago
12

Are the ratios 6:18 and 2:6 equivalent?

Mathematics
2 answers:
Ksju [112]3 years ago
7 0
Yes because 6/18=1/3 and 2/6=1/3. Then 6/18=2/6
viktelen [127]3 years ago
3 0
Treat them like fractions. Ratios are just fractions in a different form.

\frac{6}{18}  and   \frac{2}{6}

You can simplify 6/18. Find common factors. 2, 3, 6

Let's try and divide the top and bottom (numerator and denominator) by 3.
Then you get 2/6.
2/6 is equivalent to 2/6
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use the plot of the concentration of cu(no3)3 versus absorbance provided. if the absorbance of an unknown was determined to be 0
Helen [10]

Using the linear regression equation, the concentration of the unknown solution is 0.2161 M.

Linear regression describes the relationship of two variables. It may not be exact but it is the line that best fit the data. The equation for a linear regression is in the form y = bx + a, where x and y are the two variables.

If the absorbance of an unknown was determined to be 0.67 absorbance units, using the linear regression equation provided from the plot, substitute the value of absorbance to the variable y and solve for the value of x or the concentration.

y = 3.8674x - 0.1657

0.67 = 3.8674x - 0.1657

3.8674x = 0.67 + 0.1657

3.8674x = 0.8357

x = 0.2161

Hence, the concentration is 0.2161 M.

Learn more about linear regression here: brainly.com/question/25311696

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1 year ago
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harkovskaia [24]
F because 0 | 2 means 02
4 0
3 years ago
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A Estimate √690 to the nearest whole number.
Fantom [35]
Search the square root of ____ on Google
6 0
3 years ago
Use graph to answer questions
shutvik [7]

Answer:

\sin(  \alpha )  =   \frac{4}{5}

Step-by-step explanation:

as if we form an imaginary triangle with this line as hypotenuse

we get

  • base = 3 units
  • perpendicular = 4 units

using Pythagoras theorem:-

hyponteuse ² = perpendicular ² + base²

hyp² = 4² + 3²

hyp² = 16 + 9

hyp =  \sqrt{25}

hyp = 5 units

\sin( \theta )   =  \frac{perpendicular}{hypotenuse}  \\  \sin( \theta)  =  \frac{4}{5}

3 0
3 years ago
What is the result of isolating y^2 in the equation below (x-2)^2+y^2=64?
natta225 [31]

What is the result of isolating y^2 in the equation below (x-2)^2+y^2=64?

Solution:

We want to isolate y^{2} from the equation (x-2)^{2} +y^{2} =64

To isolate y^{2}, we must try to get y^{2} alone

So, We must subtract (x-2)^{2} from both sides

(x-2)^{2}-(x-2)^{2}  +y^{2} =64-(x-2)^{2}

0 +y^{2} =64-(x-2)^{2}

y^{2} =64-(x^{2}-4x+4)

Distributing '-' inside parenthesis

y^{2} =64-x^{2} +4x -4

y^{2} =60-x^{2} +4x

6 0
3 years ago
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