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garri49 [273]
3 years ago
8

A marine biologist will collect data regarding the length and weight of each of 50 trout caught and released at five different l

ocations in a given lake. Which type of visual representation would BEST represent the marine biologist’s data?
a bar graph comparing the largest trout caught at each of the five locations

a scale drawing of all trout caught regardless of location

a circle graph comparing the number of trout caught at each of the five locations

a scatterplot comparing the length and weight of each trout regardless of location
Mathematics
1 answer:
Vesnalui [34]3 years ago
3 0
I think that the best visual representation that the marine biologist would use is utilising a bar graph. A bar graph is composed of bars residing in a coordinate plane. In addition to that, the visual representation would most likely be used since the average weight and length of each trout coming from 5 different locations is compared.
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A 7-column table with 2 rows. Column 1 is labeled Sample with entries catfish, all fish. Column 2 is labeled 1 with entries 3, 2
ycow [4]

Answer: The correct option is 5.7/20 = x/200

Step-by-step explanation: Please refer to the diagram attached for more details.

From the 7-column by 2-row table drawn, you can determine that the mean number of catfish as given in the question is derived as follows;

Mean = Summation of observed data / Number of observations

Mean  = (3 + 5 + 7 + 5 + 6 + 8)/6

Mean = 34/6

Mean = 5.6667

Mean ≈ 5.7

Also the mean number of all fish is derived as follows;

Mean = Summation of observed data / Number of observations

Mean = (20 + 20 + 20 + 20 + 20 + 20)/6

Mean = 120/6

Mean = 20

Using relative frequency, we can confidently predict the number of catfish population in the pond. This simply means, if the mean number of catfish is 5.7 and the mean number of all fish is 20, then the relative frequency would be 5.7 over 20 of the total fish population.

Hence, if there is a total of 200 fish in the pond then to predict the proportion which would be catfish can be expressed as follows;

StartFraction 5.7 over 20 EndFraction = StartFraction x over 200 EndFraction.

OR better expressed as;

5.7/20 = x/200

5 0
3 years ago
An airplane is at a location 800 miles due west of city X. Another airplane is at a distance of 1,200 miles southwest of city X.
zaharov [31]

Answer:

The distance between the two airplanes (to the nearest mile) is 1058 miles.

Step-by-step explanation:

An airplane A is at a location 800 miles due west of city X. So AX = 800 miles.

Another airplane is at a distance of 1,200 miles southwest of city X. So BX = 1200 miles.

The angle at city X created by the paths of the two planes moving away from city X measures 60°. So angle ∠AXB = 60°.

In triangle ΔAXB, AX = 800 miles, BX = 1200 miles, ∠AXB = 60°.

Using law of cosines:-

AB² = AX² + BX² - 2 * AX * BX * cos(∠AXB).

AB² = 800² + 1200² - 2 * 800 * 1200 * cos(60°).

AB² = 640000 + 1440000 - 2 * 960000 * 1/2

AB² = 2080000 - 960000

AB² = 1120000

AB = √(1120000) = 1058.300524

Hence, the distance between the two airplanes (to the nearest mile) is 1058 miles.

Read more on Brainly.com - brainly.com/question/12103659#readmore

6 0
4 years ago
If LM = 16, MN = x + 18, and LN<br> 2x + 16, what is MN?
Montano1993 [528]
  • We got , x = 18.
  • So, In QUESTION, MN = x + 18 = 18 + 18 = 36.
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C Would Be Correct I Belive
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Find the area (l x w)

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