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xz_007 [3.2K]
3 years ago
15

5x – 12y – 17 = 0 1*9(x + 2) - (y + 1) + 3 = 0

Mathematics
1 answer:
valentina_108 [34]3 years ago
3 0

Answer: x=\frac{12y+17}{5}

y=\frac{-5x+17}{-12}

x=\frac{y-20}{9}

y=9x+20

Step-by-step explanation:

5x-12y-17=0 (plus 17 from both sides)

5x-12y=17 (plus 12y from both sides)

5x=12y+17 (divide 5 from everything)

x=\frac{12y+17}{5}

5x-12y-17=0 (plus 17 from both sides)

5x-12y=17 (minus 5x from both sides)

-12y=-5x+17 (divide everything by -12)

y=\frac{-5x+17}{-12}

1*9(x+2)-(y+1)+3=0 (distribute 9 to x and to 2) (distribute -1 to y and to 1)

1*9x+18-y-1+3=0 (times 9x by 1)

9x+18-y-1+3=0 (combine like terms)

9x-y+20=0 (minus 20 from both sides)

9x-y=-20 (plus y to both sides)

9x=y-20 (divide 9 from both sides)

x=\frac{y-20}{9}

1*9(x+2)-(y+1)+3=0 (distribute 9 to x and to 2) (distribute -1 to y and to 1)

1*9x+18-y-1+3=0 (times 9x by 1)

9x+18-y-1+3=0 (combine like terms)

9x-y+20=0 (minus 20 from both sides)

9x-y=-20 (minus 9x from both sides)

-y=-9x-20 (divide -1 from everything)

y=9x+20

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Please help! I've been working on this for a few days and I just don't understand, it's due in a few hours. Thank you.
never [62]

Answer:

Part A: α = arc tan (y/x) = tan⁻¹ (y/x)

Part B: quadrant II α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 180°>α>90°

            quadrant III α = arc tan (-y)/(-x) = arc tan (y/x) = tan⁻¹ (y/x) 270°>α>180°

            quadrant IV α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 360°>α>270°

Part C: quadrant II 180°>α>90°  α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 180° - 80.53° = 99.47°

Step-by-step explanation:

PART A:

In this case we will use trigonometric function tanα to calculate angle α:

tanα = y/x => α = arc tan (y/x) = tan⁻¹ (y/x)

This formula is use in general way and in first quadrant  90°>α>0°

Part B:

But in the other quadrants you must know to use unit circle to reduce angle from II, III and IV quadrant to the first quadrant.

If angle is in the quadrant II  180°>α>90° then

tanα = - tan (180°-α)

If angle is in the quadrant III  270°>α>180° then

tanα = tan (α-180°)

If angle is in the quadrant IV  360°>α>270° then

tanα =- tan (360°-α)

Part C:

vector w (x,y) = (-1,6) this vector lies in quadrant II      180°>α>90°

180°- α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 80.53°  => 180° - α = 80.53°

α = 180° - 80.53 = 99.47°

It's not easy to understand this, but it's not easy for me to explain.

God with you!!!

5 0
2 years ago
Question 4 please:<br> Witch numbers in the box are multiple of 3
umka21 [38]

Answer:

6 AND 12

Step-by-step explanation:

3 x 2 = 6

3 x 4 = 12

4 0
3 years ago
Read 2 more answers
1/2(3/4n+ 9) and 2(12 + 8x) -3(4x -9) i need help with these two
Ghella [55]
I dont know if this is right but the answer to 2(12+8x)-3(4x-9) might be 4x+51?
5 0
3 years ago
Read 2 more answers
Jaime bakes24 muffins and gives away 3. She also bakes 36 bagels and gives away 4. Writean expression using GROUPING SYMBOLS ILL
Sergeu [11.5K]

Answer:

24-3=21 , 36-4=32 ,  3+4=7 , 7 x 5 , which equals 35

Step-by-step explanation:

5 0
2 years ago
I’m not sure how to slove this problem it’s a equilateral triangle and I’m trying to find out what the side is equal to.
Lerok [7]

Answer:

AB = 5/4 y - 1  = 5/4 (12/13) -1 = 2/13

AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13

Step-by-step explanation:

Because it is a equilateral triangle, it means all sides have the same length.

AB = AC

5/4 y - 1 = 7/3 y - 2

5/4 y - 7/3 y = -2 +1

-13/12 y = -1

y = 12/13

input y to the equation.

AB = 5/4 y - 1  = 5/4 (12/13) -1 = 2/13

AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13

Please check my other articles in my site, just copy and paste this word to google search engine: learningandassignments diy4pro.

Hope it helps you.

6 0
3 years ago
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