All categories

3 years ago

A moving truck has a length that measures 10 ft, a width of 6 ft,

Mathematics

2 answers:

noname [10]3 years ago

8 0

Answer:

3660 ft^3

Step-by-step explanation:

inn [45]3 years ago

5 0

Answer:

the volume of the truck = 390 ft³

Step-by-step explanation:

given:

Length that measures 10 ft, a width of 6 ft,

and a height of 6 1/2, Ft.

find:

What is the volume of the

moving truck?

volume of a rectangular prism = L x W x H

where L = length = 10 ft.

W = width = 6 ft.

H = height = 6 1/2 ft

plugin values into the formula:

V = 10 x 6 x 6.5

V = 390 ft³

therefore,

the volume of the truck = 390 ft³

You might be interested in

the fair committed wants to decorate each ride with 40 balloons there are 13 rides if balloonso come 24 package how many package

Jet001 [13]

14x30=520. So, 520 divided by 24 = 21.6 . So, that means that you will need 22 packages of balloons and you will have 8 left over

3 0

3 years ago

Read 2 more answers

Write the equation for a parabola with a focus at (9,0) and a directrix at y = -4.

Alika [10]

Answer:

Step-by-step explanation-3:

8 0

2 years ago

Read 2 more answers

Random sample size of 81 are taken from an infinite population whose mean and standard deviation are 200 and 18, respectively. T

Ugo [173]

Answer:

the mean and standard error of the mean are 200 and 2 respectively.

Step-by-step explanation:

Given that ;

the sample size n = 81

population mean μ = 200

standard deviation of the infinite population σ = 18

A population is the whole set of values, or individuals you are interested in, from an experimental study.

The value of population characteristics such as the Population mean (μ), standard deviation (σ) are said to be known as the population distribution.

From the given information above;

The sample size is large and hence based on the central limit theorem the mean of all the means is same as the population mean 200.

i.e

$\mu = \bar \mu_x$ = 200

∴ The mean = 200

and the standard error of the mean can be determined via the relation:

$\mathbf{standard \ error \ of \ mean = \dfrac{\sigma}{\sqrt {n}}}$

$\mathbf{standard \ error \ of \ mean = \dfrac{18}{\sqrt {81}}}$

$\mathbf{standard \ error \ of \ mean = \dfrac{18}{9}}$

$\mathbf{standard \ error \ of \ mean =2}$

Therefore ; the mean and standard error of the mean are 200 and 2 respectively.

6 0

2 years ago

Find the general solution to 1/x dy/dx - 2y/x^2 = x cos x, y(pi) = pi^2

Finger [1]

Answer:

$\frac{y}{x^2}=\sin x+\pi$

Step-by-step explanation:

Consider linear differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$

It's solution is of form $y\,I.F=\int I.F\,q(x)\,dx$ where I.F is integrating factor given by $I.F=e^{\int p(x)\,dx}$ .

Given: $\frac{1}{x}\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x^2}=x\cos x$

We can write this equation as $\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x}=x^2\cos x$

On comparing this equation with $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$ , we get $p(x)=\frac{-2}{x}\,\,,\,\,q(x)=x^2\cos x$

I.F = $e^{\int p(x)\,dx}=e^{\int \frac{-2}{x}\,dx}=e^{-2\ln x}=e^{\ln x^{-2}}=\frac{1}{x^2}$ { formula used: $\ln a^b=b\ln a$ }

we get solution as follows:

$\frac{y}{x^2}=\int \frac{1}{x^2}x^2\cos x\,dx\\\frac{y}{x^2}=\int \cos x\,dx\\\\\frac{y}{x^2}=\sin x+C$

{ formula used: $\int \cos x\,dx=\sin x$ }

Applying condition: $y(\pi)=\pi^2$

$\frac{y}{x^2}=\sin x+C\\\frac{\pi^2}{\pi}=\sin\pi+C\\\pi=C$

So, we get solution as :

$\frac{y}{x^2}=\sin x+\pi$

4 0

3 years ago

Find the measure of x in the figure. show your work. answer asap please

fenix001 [56]

Answer:

x=25

Step-by-step explanation:

2x+40=90

90-40=50

50 divided by 2 is 25

x=25

5 0

2 years ago