Evaluate for the given value of the variable y x 6 for y =2/3
1 answer:
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Answer:
first answer is correct
Step-by-step explanation:
Hello, we want to write 2 + 4 + 6 + ... + 20
for n = 1, 2n = 2*1 =2
for n = 2, 2n = 2*2=4
for n = 3, 2n=2*3=6
etc
so
thanks
Answer:
4 /15
Step-by-step explanation:
From the number cube :
Count of Numbers greater than 4 = 16
Sample space of number cube = 20
P(number greater than 4) = 16 / 20 = 4/5
Word : ATTENTION
Count of letters in attention = 9
Count of T's in attention = 3
P(choosing T) = 3 / 9 = 1/3
P(greater than 4, then T) = 4/5 * 1/3 = 4 /15
cosU:-
As U lies in Q3
- cosU=-24/25
sinV
As V lies in Q3
- sinV=-3/5
So
- sin(V-U)=sinVcosU-cosVsinU=(-3/5)(-24/25)-(-4/5)(-7/25)=72/125-28/125=72-28/125=<u>4</u><u>4</u><u>/</u><u>1</u><u>2</u><u>5</u>
- cos(U-V)=cosUcosV+sinUsinV=(-24/25)(-4/5)+(-7/25)(-3/5)=96/125+21/125=117/125