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alex41 [277]
4 years ago
9

If the half-life of a radioactive substance is 2,800 years, then at what rate is it decaying?

Mathematics
1 answer:
vlada-n [284]4 years ago
6 0

Answer:

0.0001075

Step-by-step explanation:

The relation between halflife and rate at which it is decaying is given by

t_{\frac{1}{2} } =\dfrac{log2}{rate}

now in the above problem halflife is given as 2800 years substituting in the above equation we get the value of rate at which it is decaying to be rate=0.0001075.

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What is the answer? becuase i am just confused
Svetradugi [14.3K]

Answer:

Step-by-step explanation:

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3 years ago
The possible values of x are given by x−3≥2 . What is the least possible value of 5x ?
mamaluj [8]
The answer would be twenty five because x-3 \geq 2
 equals x  \geq 5 leaving you with x = 5 at a minimum. So 5x: 5 x 5 = 25

Hope this helps! :)
5 0
4 years ago
(1.1/1.2: Interpolating polynomials) Say we want to find a polynomialf(x) ofdegree 3,f(x) =a0+a1x+a2x2+a3x3,satisfying some inte
Hunter-Best [27]

(a) If

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then from the given conditions we get the system of equations,

<em>f</em> (-1) = <em>a</em>₀ - <em>a</em>₁<em> </em>+<em> a</em>₂ - <em>a</em>₃ = -1

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+ 4<em>a</em>₂ + 8<em>a</em>₃ = 1

<em>f</em> (3) = <em>a</em>₀ + 3<em>a</em>₁<em> </em>+<em> </em>9<em>a</em>₂ + 27<em>x</em> ³ = 5

(b) Similarly, if

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then

<em>f'(x)</em> = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ <em>x</em> + 3<em>a</em>₃ <em>x</em> ²

so that the given conditions yield the system,

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 0

<em>f'</em> (1) = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ + 3<em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 27<em>a</em>₃ = 3

<em>f'</em> (2) = <em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 12<em>a</em>₃ = -1

7 0
3 years ago
Show that the equation of the line passes (3,5) and (3,-7). Is it possible to what an equation of the line in slope-intercept fo
vodomira [7]

Answer: you need a x and y axis to get this answer

Step-by-step explanation: first you put the (3,5) and (3,-7) in a graph paper then make an y and x axis and you will be able to see your answer visually

5 0
3 years ago
Read 2 more answers
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