Someone please help ASAP. 15 points and I’ll mark brainliest.
1 answer:
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First, find the slope (m) = =
=
=
Now plug in ONE of the points and the slope into the point-slope equation:
y - y₁ = m(x - x₁); where (x₁, y₁) is the chosen point.
y - 5 = (x - 1) (I used (1,5) as the chosen point)
3(y - 5) = x - 1
3y - 15 = x - 1
3y -14 = x
-14 = x - 3y → x - 3y = -14
Answer: x - 3y = -14
The solution of the linear equations will be ( -2, 4).
<h3>What is an equation?</h3>It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
Given equations are:-
- 2x +3y = 8 and 3x+y= -2
Solving the equations by elimination method:-
2x +3y = 8
3x+y= -2
Multiply the second equation by 3 and subtract from the first equation.
2x +3y = 8
-9x -3y = 6
----------------
-7x = 14
x = -2
Out of the value of x in any one equation, we will get the value of y.
3x+y= -2
3 ( -2) + y = -2
-6 + y = -2
y = 4
The graph of the equations is also attached with the answer below.
Therefore the solution of the linear equations will be ( -2, 4).
The complete question is given below:-
Exploring Systems of Linear Equations 2x +3y =8 and 3x+y= -2. Find the value of x and y and draw a graph for the system of linear equations.
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