All categories

3 years ago

Someone please help ASAP. 15 points and I’ll mark brainliest.

Mathematics

1 answer:

lyudmila [28]3 years ago

3 0

Answer:

first is linear second is quadratic and third looks like linear

Step-by-step explanation:

1. its a continuous straight line, linear

2. parabola shaped, quadratic

3. again a straight line, so linear

You might be interested in

Complete the input-output table that represents the linear function y=−2x+8.

Fofino [41]

You substitute the x with 1
Y=-2x(1)+8

So y = 6

3 0

3 years ago

Using six random samples, the average number of catfish in the samples was 5.7. If the total population of fish in the pond is 2

zheka24 [161]

Using the proportion given, there will be 57 catfish in the pond.

The proportion given to us is
5.7/20 = x/200

Cross multiply:
5.7*200 = 20*x
1140 = 20x

Divide both sides by 20:
1140/20 = 20x/20
57 = x

5 0

3 years ago

Read 2 more answers

A farmer wants to use 200 feet of fencing for a chicken pen. He wants the width of the pen to be 20 feet. What is the length of

Aneli [31]

The length should be 80 feet.

This is because the width is 20, since there are two sides for the width in a pen, we have to add 20+20. This would equal 40. Then we need to subtract 40 from 200. 200-40 would be 160. Then since there are two sides for the length, we need to split that in half. 160÷2 would be 80. To double check, you can do 80+80 and that would still be 160. So the length of one side would be 80. But of course, this whole thing would only be right if the pen has four sides(but since i have seen many chicken pens, there were all rectangular). I hope this helped! :)

7 0

3 years ago

The population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t. After 3 hours

Arada [10]

Answer:

The number of bacteria at initial = 187

Step-by-step explanation:

Given that the population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t.

$\frac{dN}{dt} = k N$

$\frac{dN}{N} = k dt$

Integrating both side we get

㏑ N = k t + C ------- (1)

Now given that after 3 hours it is observed that 500 bacteria are present and after 10 hours 5000 bacteria are present.

⇒ ㏑ 500 = 3 k + C -------- (2)

⇒ ㏑ 5000 = 10 k + C ------ (3)

⇒ ㏑ 5000 - ㏑ 500 = 7 k

⇒ ㏑ $\frac{5000}{500}$ = 7 k

⇒ ㏑ 10 = 7 k

⇒ k = 0.329

Put this value of k in equation (2),

⇒ ㏑ 500 = 3 × 0.329 + C

⇒ C = 5.23

Put this value of C in equation 1 we get,

⇒ ㏑ N = k t + 5.23

Initially when t = 0 , then

⇒ ㏑ N = 5.23

⇒ N = 187

Thus the number of bacteria at initial = 187

8 0

3 years ago

Jane had of a meter of ribbon. She used of a meter of ribbon to decorate a card. How much ribbon did she have left after she dec

emmainna [20.7K]

She had none left. if she only had a meter and then used a meter there would be none left.

5 0

2 years ago