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9966 [12]
2 years ago
12

When 37299 is divided by a number , the quotient is 298 and the remainder is 49. what is the number?​

Mathematics
2 answers:
alisha [4.7K]2 years ago
8 0

Answer:

\huge\boxed{125}

Step-by-step explanation:

n-\text{a number}\\\\298n+49=37299\qquad|\text{subtract 49 from both sides}\\\\298n+49-49=37299-49\\\\298n=37250\qquad|\text{divide both sides by 298}\\\\\dfrac{298n}{298}=\dfrac{37250}{298}\\\\n=125

photoshop1234 [79]2 years ago
8 0

Answer:

11,115,151

Step-by-step explanation:

I multiplied 37,299 by 298 then I added the number by 49 and got 11,115,151

I then divided 37,299 and 11,115,151 and got 298 and some numbers after it.

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Use the distributive property to expand the linear expression. 3(4x + 3) A) 3 4 B) 12x + 6 C) 12x + 9 D) -3 4
kipiarov [429]

Answer:

<h2>C) 12x + 9</h2>

Step-by-step explanation:

The distributive property: <em>a(b + c) = ab + ac</em>.

3(4x+3)=(3)(4x)+(3)(3)=12x+9

8 0
3 years ago
Select the equation of the line parallel to the equation y = -2x - 7 that passes through the point (3, 1). y = -2x + 7 y = -2x +
Vilka [71]
Y - y₁ = m(x - x₁)
 y - 1 = -2(x - 3)
 y - 1 = -2(x) + 2(3)
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The answer is A.

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Answer:

21w+3

Step-by-step explanation:

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Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d to test whether any of them is a solution. a. 23 is a solution. c. 24
S_A_V [24]

Answer:

c. 24 is a solution

Step-by-step explanation:

Given equation:

\frac{4}{3}=\frac{32}{d}

To test the numbers 22, 23, 24, 25 for the solution.

Solution:

In order to test the given number for the solution, we will plugin each number in the unknown variable d and see if it satisfies the equation.

1) d=22

\frac{4}{3}=\frac{32}{22}

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

\frac{4}{3}=\frac{32\div 2}{22\div 2}

\frac{4}{3}=\frac{16}{11}

The above statement can never be true and hence 22 is not a solution.

2) d=23

\frac{4}{3}=\frac{32}{23}

The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

3) d=24

\frac{4}{3}=\frac{32}{24}

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

\frac{4}{3}=\frac{32\div 8}{24\div 8}

\frac{4}{3}=\frac{4}{3}

The above statement is always true and hence 24 is a solution.

4) d=25

\frac{4}{3}=\frac{32}{25}

The fractions can no further be reduced.

The statement can never be true and hence 25 is not a solution.

4 0
2 years ago
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