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pochemuha
3 years ago
8

12x−39≤9 AND−4x+3<−6

Mathematics
2 answers:
nignag [31]3 years ago
8 0

Answer:

2 1/4 < x ≤ 4

Step-by-step explanation:

12x−39≤9 AND−4x+3<−6

Solve them separately and then put back together

12x−39≤9

Add 39 to each side

12x−39+39≤9+39

12x ≤48

Divide by 12

12x/12 ≤48/12

x ≤4

Now the other inequality

−4x+3<−6

Subtract 3 from each side

−4x+3-3<−6-3

-4x < -9

Divide by -4, remembering to flip the inequality

-4x/-4 > -9/-4

x > 2 1/4

put back together

x > 2 1/4 and x ≤4

2 1/4 < x ≤ 4

densk [106]3 years ago
5 0

Answer:

2.25<x≤4

Step-by-step explanation:

12x−39≤9 ⇒ 12x≤ 48 ⇒ x≤4

−4x+3<−6 ⇒ -4x < -9 ⇒ x> 9/4= 2.25

2.25<x≤4

or

x= (2.25, 4]

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Answer:

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Alternative hypothesis:\mu \neq 100  

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Step-by-step explanation:

1) Data given and notation  

Data: 105.6, 90.9, 91.2, 96.9, 96.5, 91.3, 100.1, 105.0, 99.6, 107.7, 103.3, 92.4

We can calculate the sample mean and deviation for this data with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

The results obtained are:

\bar X=98.375 represent the sample mean  

s=0.6.109 represent the sample standard deviation  

n=12 sample size  

\mu_o =100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

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t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

4) P-value  

First we need to find the degrees of freedom for the statistic given by:

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5) Conclusion  

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Step-by-step explanation:

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