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Ivan
3 years ago
15

The circle below is centered at the point 8.4 and has a radius of length 4 what is its equation​

Mathematics
1 answer:
pshichka [43]3 years ago
8 0

Answer:

16

Step-by-step explanation:

(x-8)^2 + (y-4)^2= 16

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Hey, I really need some help figuring out this question.
Alexandra [31]

Answer:

it's d

Step-by-step explanation:

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6 0
3 years ago
I don’t understand the equation
ankoles [38]

you need to find to find the value of x and y.

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6 0
3 years ago
If a= m2 + 2, what is the value of a when m=-3?<br> 0-7<br> -4<br> 11<br> 00
vladimir1956 [14]

Answer:

a=11

Step-by-step explanation:

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6 0
3 years ago
Find the point on the curve y = √ x where the tangent line is parallel to the line y = x 8 .
vichka [17]
If tangent to the curve y = √x  is parallel to the line  y = 8x,  then this implies that the tangent to  y = <span>√x  has the same slope as the line  y = 8x. In other words, the derivative (slope) function of  y = √x  is equal to the slope of the line  y = 8x, which is m = 8.  Hence y' = 8  once we find  y'

y =  </span><span>√x = x^(1/2)

Applying the power rule and simplifying, we find that the derivative is

y' = 1/(2</span>√x)

Now remember that  y'  must equal 8

1/(2<span>√x) = 8

Multiplying both sides by  2</span><span>√x,  we obtain

1 = 16</span><span>√x

Dividing both sides by  16,  yields

</span><span>√x = 1/16

But wait a minute, √x = y.  Thus  1/16  must be the y-coordinate of the point at which the tangent to  y = √x  is drawn.

Squaring both sides, yields

x = 1/256 

This is the x-coordinate of the point on the curve where the tangent is drawn.

</span><span>∴ the required point must be  (1/256, 1/16)

GOOD LUCK!!!</span>
7 0
3 years ago
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