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3 years ago

Help plz also show work

Mathematics

1 answer:

Maslowich3 years ago

6 0

Answer:

B 84

Step-by-step explanation:

Angles P and R are complementary, so ...

(2x -6) + (3x -24) = 90

5x -30 = 90 . . . collect terms

x -6 = 18 . . . . . divide by 5

x = 24 . . . . . . . add 6

∠P = (2x-6)° = (2·24 -6)° = 42°

The measure of arc SR is twice the measure of ∠P, so is ...

arc SR = 2·42° = 84°

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Let measure angle A equal 40. If angle B complement of angle A, and angle C is a supplemlement of angle B find these measures

uranmaximum [27]

Two angles are complementary when they add up to 90 degrees
m∠B = 90° - m∠A = 90° - 40° = 50°

Two angles are supplementary when they add up to 180 degrees
m∠C = 180° - m∠B = 180° - 50° = 130°

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3 years ago

<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20Find%20the%20value%20of%20%7D%20%5Cfrac%7B

ankoles [38]

$\bold{Heya!}$

Your answer to this is:

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

<h2>→ EXPLANATION :-</h2>

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)$

$\sf{Apply \: rule:} \: (a) = a$

$\sf{(1) = 1$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1$

$\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}$

$\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

$\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}$

Hopefully This Helps ! ~

#LearnWithBrainly

$\underline{Answer :}$

Jaceysan ~

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denis23 [38]

Answer:

Step-by-step explanation:

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