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Vsevolod [243]
3 years ago
13

Help plz also show work

Mathematics
1 answer:
Maslowich3 years ago
6 0

Answer:

  B  84

Step-by-step explanation:

Angles P and R are complementary, so ...

  (2x -6) + (3x -24) = 90

  5x -30 = 90 . . . collect terms

  x -6 = 18 . . . . . divide by 5

  x = 24 . . . . . . . add 6

∠P = (2x-6)° = (2·24 -6)° = 42°

The measure of arc SR is twice the measure of ∠P, so is ...

  arc SR = 2·42° = 84°

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The estimate of the population proportion should be within plus or minus 0.02, with a 90% level of confidence. The best estimate
Rudiy27

Answer:

The sample size required is 910.

Step-by-step explanation:

The confidence interval for population proportion is:

CI=\hat p\pm z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }

The margin of error is:

MOE=z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }

Given:

\hat p = 0.16\\MOE= 0.02\\Confidence\ level =0.90

The critical value of <em>z</em> for 90% confidence level is:

z_{\alpha /2}=z_{0.10/2}=z_{0.05}=1.645 *Use a standard normal table.

Compute the sample size required as follows:

MOE=z_{ \alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }\\0.02=1.645\times \sqrt{\frac{0.16(1-0.16)}{n} }\\n=\frac{(1.645)^{2}\times 0.16\times (1-0.16)}{(0.02)^{2}} \\=909.2244\\\approx910

Thus, the sample size required is 910.

5 0
3 years ago
The lifespans of gorillas in a particular zoo are normally distributed. The average gorilla lives 20.8 years; the
Luda [366]
If the mean is 20.8, one standard deviation each way is adding and subtracting 3.1, so 17.7 and 23.9 (68% of values)

Two standard deviations adding and subtracting 3.1*2 = 6.2, or 14.6 and 27.

Three standard deviations is 11.5 and 30.1

So we have
11.5 - 14.6 - 17.7 - 20.8 - 23.9 - 27 - 30.1

Going left to 11.5 is 3 standard deviations out, so 99.7/2 = 49.85%

Going right to 27 is 2 standard deviations out, so 95/2 = 47.5%

Add those two % to get 97.32%

This is hard to do without a picture so I hope that helps!

3 0
3 years ago
Add the polynomials. <br> (7y^2+2y-9)+(-3y^2-y) = ?
Vikki [24]
(7 y^{2}  + 2y - 9) + (-3 y^{2} -y) \\ &#10; \\ &#10;= 4y^{2} + y - 9
3 0
3 years ago
Which of the following is true of rounding the optimized solution of a linear program to an integer?
VashaNatasha [74]

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

the optimized solution of a linear program to an integer as it does not affect the value of the objective function.

As if we round the optimized solution to the nearest integer, it does not change the objective function .

while it is not true that it always produces the most optimal integer solution or feasible solution.

Hence, Option 'c' is correct.

6 0
3 years ago
Question 6
inna [77]

Answer:

add, subtract, multiply and divide complex numbers much as we would expect. We add and subtract

complex numbers by adding their real and imaginary parts:-

(a + bi)+(c + di)=(a + c)+(b + d)i,

(a + bi) − (c + di)=(a − c)+(b − d)i.

We can multiply complex numbers by expanding the brackets in the usual fashion and using i

2 = −1,

(a + bi) (c + di) = ac + bci + adi + bdi2 = (ac − bd)+(ad + bc)i,

and to divide complex numbers we note firstly that (c + di) (c − di) = c2 + d2 is real. So

a + bi

c + di = a + bi

c + di ×

c − di

c − di =

µac + bd

c2 + d2

¶

+

µbc − ad

c2 + d2

¶

i.

The number c−di which we just used, as relating to c+di, has a spec

7 0
3 years ago
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