See photo for the answers and solutions.
Answer:
AB = CD
5 - x^2 = -6x + 13
- x^2 - 8 = -6x
- x^2 + 6x - 8 = 0
x^2 - 6x + 8 = 0
Because 2 * 4 = 8 and 2 + 4 = 6
the solutions are
x = 2 or x = 4
You can also use the pq or abc-formula to solve a quadratic equation.
That expression represents a number that is
7 more than one quarter of the number 'd'.
When looking at expressions like this,, you need to remember that the square root of a negative number does not exist in the set of Real Numbers. This means that there is no way to simplify this expression,, making the correct answer to your question Undefined.
Let me know if you have any further questions.
:)
You use the quadratic formula:
2x {}^{2} - 3x = 5
2x {}^{2} - 3x - 5 = 0
x = \frac{3 + - \sqrt{9 -4(2)( - 5)}}{2 \times 2}
x = \frac{3 + - \sqrt{49} }{4}
x = \frac{3 + 7}{4} \: and \: x = \frac{3 - 7}{4}
x = \frac{5}{2} \: and \: x = - 1