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3 years ago

Plzzz help mrrrrrrr aaaaaaaaaaaaaaaaaaaaa

Mathematics

2 answers:

Artemon [7]3 years ago

7 0

Answer:

x=7

Step-by-step explanation:

Solve.

7x-5x-3=x+4

Calculate like terms.

7x-5x=2x

Rearrange.

2x-3=x+4

Apply inverse addition.

2x-3+3=x+4+3

2x=x+7

Isolate 2x by subtraction.

2x-x=x-x+7

x=7

victus00 [196]3 years ago

7 0

Answer:

Here's your answer Option B - x =7.

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Step-by-step explanation:

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3 years ago

Read 2 more answers

a rectangular dog kennel is to be constructed alongside a house with 60m of fencing. If the house serves as one side of the kenn

Basile [38]

Answer:

$450\text{ m}^2$ .

Step-by-step explanation:

Let x represent side of kennel opposite to house and y represent other sides.

We have been given that a rectangular dog kennel is to be constructed alongside a house with 60 m of fencing.

Since fencing will cover 3 sides of kennel, so perimeter of kennel would be:

$x+y+y=60$

$x+2y=60$

Let us solve for x.

$x+2y-2y=60-2y$

$x=60-2y$

The area of the kennel would be product of its sides that is:

$\text{Area}=x\cdot y$

Now, we will substitute $x=60-2y$ in area equation as:

$A(y)=(60-2y)\cdot y$

$A(y)=60y-2y^2$

Let us find the derivative as shown below:

$A'(y)=60-4y$

Now, we will set derivative equal to 0 and solve for y.

$60-4y=0$

$60=4y$

$\frac{60}{4}=\frac{4y}{4}$

$y=15$

Upon substituting $y=15$ in area function, we will greatest possible area.

$A(y)=60y-2y^2$

$A(15)=60(15)-2(15)^2$

$A(15)=900-2(225)$

$A(15)=900-450$

$A(y)=450$

Therefore, the greatest possible area that can be enclosed by 60 m of fencing is 450 square meters.

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3 years ago

What adds to 90 and multiples to 2025

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45!

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3 years ago

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Furkat [3]

Answer:

Step-by-step explanation:

Angles ABO, BAO, and AOB are the angles of isosceles triangle AOB. The angles at A and B are equal, so we have ...

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3 years ago