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Sophie [7]
3 years ago
6

Find the distance between k and l

Mathematics
2 answers:
yuradex [85]3 years ago
8 0
You have to shift 5 to the right
stira [4]3 years ago
7 0
Shift 5 to the right
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The rounding rule for the correlation coefficient requires three decimal places true or false
mihalych1998 [28]
<span>Round the value of r to 3 decimal places = Answer is True</span>
6 0
3 years ago
Read 2 more answers
Y&gt;1 and y&gt;x on a graph
zlopas [31]

So,

y>1\wedge y>x

1. Graph each inequality separately.

2. Choose a test point to determine which side of the line needs to be shaded.

3. The solution to the system will be the area where the shadings from each inequality overlap one another (purple area)

As for the system of inequalities we say it's unbounded.

3 0
3 years ago
30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 &lt;0
Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}

2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)

\mathrm{Simplify}

-2logx^3-3

\mathrm{Add\:}3\mathrm{\:to\:both\:sides}

-2logx^3-3+3

\mathrm{Simplify}

-2logx^3

Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)

\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)

\mathrm{Simplify}

2lx^3og>2\log ^3\left(x\right)-3

\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0

\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\

\mathrm{Simplify}

g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0

Step-by-step explanation:

6 0
3 years ago
How do i find the slant asymptope of x^3/(2(x+2)(x-4) aka x^3/(2x^2-8)
hram777 [196]
I’m really sorry I just don’t know I guess I’m. It smart enough try to look it up and wait for someone else to answer sorry again :(
6 0
3 years ago
The area of a triangle whose height is 1 more than 6 times it’s base is 13 square feet. If the base of the triangle is x feet wh
fredd [130]
Area of a triangle: A= 1/2(base)(hieght)

base=x
height= 6(base)+1= 6x+1

13= 1/2 × (x)(6x+1) 
(get rid of 1/2 by multiplying each side by 2)
26= (x)(6x+1)
26= (x × 6x)= 6x² (x × (+1))= x
26= 6x² + x
0= 6x²+x-26


Are either of those the answers? If not, list the options and I will be able to tell you which one is correct. Hope this helped!

5 0
3 years ago
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