Answer:
Part A: Describe how you can decompose this shape into triangles: If you draw a line from each vertex to the vertex at the opposite side of the hexagon, you will form 6 triangles.
Part B: What would be the area of each triangle: 62.4
Part C: Using your answers above, determine the area of the table's surface: 374 .4
Step-by-step explanation:
Part A: Describe how you can decompose this shape into triangles: If you draw a line from each vertex to the vertex at the opposite side of the hexagon, you will form 6 triangles.
Part B: What would be the area of each triangle: bxh /2
12 x 10.4 /2
Part C: Using your answers above, determine the area of the table's surface: 374.4
Answer:
Population of monkeys after 2 years = 3200
Step-by-step explanation:
Total number of monkeys at the start = 2975
Increase ratio of monkey population one year = 
∴ New population of monkeys after 1 year= 
Decrease ratio the next year = 
∴ Population of monkeys after 2 years= 
Answer:
8p∧2 ± p - 1 ± 13/p ± 1
Step-by-step explanation:
Divide (9p2 + 8p3 + 12) ÷ (p + 1) and it equals 8p∧2 ± p - 1 ± 13/p ± 1
Answer:
Can't read the picture. Please take a bigger picture of the triangle.
The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
