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3 years ago

Which figures are similar

Mathematics

2 answers:

larisa [96]3 years ago

6 0

The Figueroa E and F are same

vampirchik [111]3 years ago

5 0

Answer:

Figure A is similar to figure C.

Figure B is similar to figure D.

Figure E is similar to figure F.

Step-by-step explanation:

We have been given 6 figures. We are asked to find similar figures.

We know that similar figures are similar if they have same shape. The size of figures can be different.

Upon looking at our given figures, we can see that figure A is a cuboid and figure C is a cuboid as well, therefore, figure A is similar to figure C.

We can see that figure B is a rectangle and figure D is rectangle as well, therefore, figure A is similar to figure C.

We can see that figure E is a right triangle and figure F is right triangle as well, therefore, figure E is similar to figure F.

You might be interested in

Enter the first 8 terms of the sequence with f(1) = 42 and f(n) = f(n − 1) − 5 for each whole number greater than 1.

Elenna [48]

F(1) = 42
f(n) = f(n-1) - 5

f(2) = f(1) - 5
f(2) = 42-5
f(2) = 37

a1 = 42
a2 = 37
r = 5
PA: (42, 37, 32, 27, 22, 17, 12, 7)

7 0

3 years ago

Evaluate the<br> expression below when<br> a= -5 and b= 2<br> 0.5a - 2b

mario62 [17]

Answer:

Step-by-step explanation:

0.5(-5) - 2(2)

= -0.25 - 4

= -4.25

8 0

3 years ago

The author drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed

algol [13]

Answer:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

$p_v = P(\chi^2_{5} >5.860)=0.32$

Since the p value is higher than the significance level assumed 0.05 we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we can assume that we have equally like results.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Number: 1, 2 , 3 , 4 , 5 ,6

Frequency: 27, 31, 42, 40, 28, 32

We need to conduct a chi square test in order to check the following hypothesis:

H0: The outcomes are equally likely.

H1: The outcomes are not equally likely.

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The observed values are given:

$O_{1}=27$ $O_{2}=31$

$O_{3}=42$ $O_{4}=40$

$O_{5}=28$ $O_{6}=32$

The expected values are given by:

$E_{1} =\frac{1}{6}*200=33.33$ $E_{2} =\frac{1}{6}*200=33.33$

$E_{3} =\frac{1}{6}*200=33.33$ $E_{4} =\frac{1}{6}*200=33.33$

$E_{5} =\frac{1}{6}*200=33.33$ $E_{6} =\frac{1}{6}*200=33.33$

And now we can calculate the statistic:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

Now we can calculate the degrees of freedom for the statistic given by:

$df=Categories-1=6-1=5$

And we can calculate the p value given by:

$p_v = P(\chi^2_{5} >5.860)=0.32$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(5.860,5,TRUE)"

4 0

4 years ago

Which statement is true regarding the angles in the figure below?

Nesterboy [21]

An exterior angle is an angle supplementary to one of the interior angles.

In other words, an exterior angle is the angle between one of the sides, and the extension of an adjacent side.

In the given diagram, the angle D is measured from one of the sides, but not to the extension of an adjacent side.

Therefore angle D is not an exterior angle.

Option D is the correct one!

8 0

3 years ago

Read 2 more answers

A frog hops 1 1/2 inches and then another 1 1/4 inches. How far has it hopped altogether?

LenKa [72]

Answer:

Add

11 over 2

11 2 + 11 over 4 11 4 = 33 over 4 33 4

Step 1 of 2: Add. Show the work

Step 2 of 2: Simplify.

Simplify

33 over 4 33 4 = 8 and 1 over 48

Step-by-step explanation:

6 0

4 years ago