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lapo4ka [179]
3 years ago
11

Somebody, please help me. Please show the work too

Mathematics
2 answers:
Leni [432]3 years ago
4 0

Answer:

x=49

Step-by-step explanation:

lina2011 [118]3 years ago
3 0

Answer:

x = 48

Step-by-step explanation:

0.75x - 9 = 27 / + 9

0.75x = 36 / : 0.75

x = 48

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Antonio pays y dollars per visit to his fitness center and he pays his bills every 3 months . In October he visited the gym 22 t
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Inmultirea fractiilor​
alexandr1967 [171]

Answer:

First, draw a rectangle and draw 3 lines going vertically. Then, draw the diagonal lines (shown in step 3) write the 4 digit number you are multiplying with the 1 digit number on top of the table (step 2) and multiply, when you are done multiplying, add the numbers vertically. Finally, you have your answer

Step-by-step explanation:

3 0
2 years ago
21:29
Mama L [17]
Yes it is the answer that is last on the list because it is that answer
6 0
3 years ago
Find each measure <br><br> Please help me
Crazy boy [7]

Answer:

see explanation

Step-by-step explanation:

∠ YXW = ∠ ZXV ( vertically opposite angles ) , so

4a + 15 = 2a + 65 ( subtract 2a from both sides )

2a + 15 = 65 ( subtract 15 from both sides )

2a = 50 ( divide both sides by 2 )

a = 25

Then

(7)

∠ ZXV = 2a + 65 = 2(25) + 65 = 50 + 65 = 115°

(8)

∠ YXW = ∠ ZXV = 115°

∠ ZXY and ∠ ZXV are adjacent angles and sum to 180° , that is

(9)

∠ ZXY = 180° - 115° = 65°

(10)

∠ VXW = ∠ ZXY = 65° ( vertically opposite angles

8 0
3 years ago
The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct
lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

y=\dfrac{x}{1+x}

Point P\left(1,\dfrac{1}{2}\right) lies on the curve.

Point Q\left(x,\dfrac{x}{1+x}\right) is an arbitrary point on the curve.

The slope of the secant line PQ is

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]

1. If x=0.5, then the slope is

\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333

2. If x=0.9, then the slope is

\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632

3. If x=0.99, then the slope is

\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513

4. If x=0.999, then the slope is

\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501

5. If x=1.5, then the slope is

\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2

6. If x=1.1, then the slope is

\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381

7. If x=1.01, then the slope is

\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488

8. If x=1.001, then the slope is

\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499

7 0
3 years ago
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