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denpristay [2]
3 years ago
11

Can anyone help me with this please

Mathematics
1 answer:
expeople1 [14]3 years ago
8 0

Answer:

Your answer would be C

Step-by-step explanation:

You might be interested in
Xsquared+11x+28+xsquared+13x+40
UNO [17]
X² + 11x + 28 + x² + 13x + 40

combine like terms

x² + x² = 2x²
11x + 13x = 24x
28 + 40 = 68

2x² + 24x + 68 is your answer

if you want it simplified: 

2(x² + 12x + 34)
   

hope this helps


5 0
3 years ago
If (fx)=5x, what is f^-1(x)
zysi [14]

Answer:

x/5

Step-by-step explanation:

To get the inverse function you need to leave the x alone and then switch variables ( f(x) = y)

f(x) = 5x

y = 5x

y/5 = x

Now that x is alone you switch the x for y and the y for x and you get:

x/5 = y

And this new y is the inverse function of f(x) ( f^-1(x))

f^-1(x) = x/5

6 0
3 years ago
Nigel travels a total of 312 miles to school each day. He walks 14 mile to the bus stop. He travels 234 miles on the city bus. I
Valentin [98]
The bus drops Nigel off 64 miles away from the school.

Step by step Explanation:

An equation for this would be 312-14-234 (this was the equation I used. Since you would do left to write to solve the equation, you would do, 312-14 which equals 298. Then, the equation is left as 298-234, and when you solve that part to the equation, yoh would be getting 64. And that's how you would get the answer 64miles away from the school.
7 0
3 years ago
Superman was said to be "faster than a speeding bullet." A Winchester rifle bullet travels at a speed of 1,924 miles per hour (m
stealth61 [152]

Answer by YourHope:


Hoi! uwu


Superman was said to be "faster than a speeding bullet." A Winchester rifle bullet travels at a speed of 1,924 miles per hour (mph). Which of the equations, where T is the time in hours and D the distance in miles, describe a speed faster than the speed of a Winchester bullet?


B= d=1,492t!

and

D= d=2,000t!


:)

7 0
3 years ago
When and how do you use logarithms to solve exponential equations? give an example of an exponential equation that does not requ
tatuchka [14]
\bf 5^{x+3}=\cfrac{1}{125}\implies 5^{x+3}=\cfrac{1}{5^3}\implies 5^{x+3}=5^{-3}
\\\\\\
\textit{because the bases are the same, the exponents must also be the same}
\\\\\\
x+3=-3\implies \boxed{x=-6}\\\\
-------------------------------\\\\
3^x=4^{2x}\implies log(3^x)=log(4^{2x})\implies xlog(3)=(2x)log(4)
\\\\\\
\cfrac{x}{2x}=\cfrac{log(4)}{log(3)}\implies \cfrac{1}{x}=\cfrac{log(4)}{log(3)}\implies \cfrac{log(3)}{log(4)}=x\implies \boxed{0.79248125\approx x}
6 0
3 years ago
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