Let x=large boxes and y=small boxes.
x+y=110
60x+35y=5100
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You need to cancel out one of the variables to solve for one. Let's cancel out y.
-35(x+y=110)
-35x-35y=-3850
60x+35y=5100
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Add the two equations.
25x=1250
x=50
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Plug in 50 for x into one of the equations to solve for y.
50+y=110
y=60
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50 large boxes
60 small boxes
Answer:
I think right answer is integers
Answer:
D
Step-by-step explanation:
If y = log x is the basic function, let's see the transformation rule(s):
Then,
1. y = log (x-a) is the original shifted a units to the right.
2. y = log x + b is the original shifted b units up
Hence, from the equation, we can say that this graph is:
** 2 units shifted right (with respect to original), and
** 10 units shifted up (with respect to original)
<u><em>only, left or right shift affects vertical asymptotes.</em></u>
Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.
Answer choice D is right.
To find the answer, we multiply 1,047.30 by 6.2% which is 0.062 in percentage.
1047.30 x 0.062 = 64.93
64.93 is being taken away.
Using binomial distribution where success is the appearing of any of the top 10 most common names, thus probability of success (p) is 9.6% = 0.096 and the probability of failure = 1 - 0.096 = 0.904. Number of trials is 11.
Binomial distribution probability is given by P(x) = nCx (p)^x (q)^(n - x)
Probability that none of the top 10 most common names appears is P(0) = 11C0 (0.096)^0 (0.904)^(11 - 0) = (0.904)^11 = 0.3295
Thus, the probability that at least one of the 10 most common names appear is 1 - 0.3295 = 0.6705
Therefore, I will be supprised that none of the names of the authors were among the 10 most common names given that the probability that at least one of the names appear is 67%.
