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3 years ago

6

What is the surface area of the figure below? Use 3.14 for Pi.

1 answer:

BartSMP [9]3 years ago

3 0

Answer:

132.52 $cm^{2}$

Step-by-step explanation:

radius=3

Area of circle= 3.14x3 squared

=28.26

28.26x2=56.52

area of rectangle=76

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1/5 times 1/5 times 100

IgorLugansk [536]

Answer:

1/1000

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A square coffee shop has sides that are 5 meters long. What is the coffee shop's area?

g100num [7]

Answer:

<h2>25m²</h2>

Step-by-step explanation:

If you want to find the area, you have to use this formula:

Formula:

LxW

L: length

W: Width

Here we have a square, and the sides are all 5 meters long, that means that we have to just do 5x5 to get the answer.

5x5=?

Hope ya remember the 5 table, lol, I know everyone does

5x5=25

so hence, your answer is 25m²

Thanks!

Answered by: FieryAnswererGT

#learnwithbrainly

8 0

3 years ago

Assume that 0 a) 25/24 b) -25/24 c) 24/25 d) -24/25

ser-zykov [4K]

A) 25/24 because i don’t know i’m just doing this to get points

8 0

3 years ago

Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)

babunello [35]

$\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k$

We want to find $f(x,y,z)$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=x^2+y$

$\dfrac{\partial f}{\partial y}=y^2+x$

$\dfrac{\partial f}{\partial z}=ze^z$

Integrating both sides of the latter equation with respect to $z$ tells us

$f(x,y,z)=e^z(z-1)+g(x,y)$

and differentiating with respect to $x$ gives

$x^2+y=\dfrac{\partial g}{\partial x}$

Integrating both sides with respect to $x$ gives

$g(x,y)=\dfrac{x^3}3+xy+h(y)$

Then

$f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)$

and differentiating both sides with respect to $y$ gives

$y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C$

So the scalar potential function is

$\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}$

By the fundamental theorem of calculus, the work done by $\vec F$ along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it $L$ ) in part (a) is

$\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}$

and $\vec F$ does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them $L_1$ and $L_2$ ) of the given path. Using the fundamental theorem makes this trivial:

$\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3$

$\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4$

8 0

3 years ago

How does supply and demand affect consumers?

mezya [45]

Supply and demand affects prices which affects consumers want and likelihood of buying a product

5 0

2 years ago