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navik [9.2K]
3 years ago
12

一、225 + 4.8 I don’t understand it plz help (And do it step by step...)

Mathematics
1 answer:
nalin [4]3 years ago
5 0

\bf -\sqrt{225}+4.8~~ \begin{cases} 225=&3\cdot 3\cdot 5\cdot 5\\ &3^2\cdot 5^2\\ &(3\cdot 5)^2\\ &15^2 \end{cases}\\\\\\ -\sqrt{15^2}+4.8\implies -15+4.8\implies -10.2

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Help please really needed
Anarel [89]

Answer:

Either :

1/2 10x+1/2 20y+1/2 10z

or

5x+10y+5z

Step-by-step explanation:

You're just multiplying everything by 1/2

7 0
3 years ago
Which set of side lengths can form a triangle?
professor190 [17]

Step-by-step explanation:

6 cm, 8 cm, and 10 cm (B) form a triangle.

The Triangle Inequality Theorem states that the sum of the lesser two sides must be greater than the third.

7 0
2 years ago
Calculate the flux of the vector field F⃗ (x,y,z)=(exy+9z+4)i⃗ +(exy+4z+9)j⃗ +(9z+exy)k⃗ through the square of side length 3 wit
ikadub [295]

The square (call it S) has one vertex at the origin (0, 0, 0) and one edge on the y-axis, which tells us another vertex is (0, 3, 0). The normal vector to the plane is \vec n=\vec\imath-\vec k, which is enough information to figure out the equation of the plane containing S:

(x\,\vec\imath+y\,\vec\jmath+z\,\vec k)\cdot(\vec\imath-\vec k)=0\implies x-z=0\implies z=x

We can parameterize this surface by

\vec s(x,y)=x\,\vec\imath+y\,\vec\jmath+x\,\vec k

for 0\le x\le\frac3{\sqrt2} and 0\le y\le3. Then the flux of \vec F, assumed to be

\vec F(x,y,z)=(e^{xy}+9z+4)\,\vec\imath+(e^{xy}+4z+9)\,\vec\jmath+(9ze^{xy})\,\vec k,

is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\iint_S\vec F(\vec s(x,y))\cdot\vec n\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_0^{3/\sqrt2}\left((4+e^{xy}+9x)\,\vec\imath+(9+e^{xy}+4x)\,\vec\jmath+(e^{xy}+9x)\,\vec k\right)\cdot(\vec\imath-\vec k)\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_0^{3/\sqrt2}4\,\mathrm dx\,\mathrm dy=\boxed{18\sqrt2}

3 0
3 years ago
A club has 10 members.
TEA [102]
That is the combination of 10 over 3, which is calculated as the quotient of factorials:
n!/k!(n-k)!
where n = 10 and k = 3:
= 10!/3!(10 - 3)!
= 10!/3!*7!
= (10*9*8)/(3*2*1)
= 720/6
= 120
therefore there a re 120 possible different groups
6 0
3 years ago
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Melissa has a choice of two phone plans
harina [27]
What are the plans?
( Sorry if not answering real question.)
4 0
3 years ago
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