1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vivado [14]
3 years ago
7

4000 principal earning 7% compounded annually , 7 years

Mathematics
1 answer:
katrin [286]3 years ago
5 0
4000×7×7÷100 that is your answer u have to divide it
You might be interested in
Find the area of each figure below. Round to the nearest hundredth when necessary. 9.6 25.4 m 12 m 10 m
adelina 88 [10]
The First person that wrote there answer is correct
6 0
3 years ago
-3 -2e -7 = 10<br> e = <br><br> Solve for e
insens350 [35]

Answer:e=-10

Step-by-step explanation:

-2e-7=13

-2e=20

e=-10

6 0
3 years ago
Read 2 more answers
-.25y is less than or equal to 16
jolli1 [7]
-25 is less than 16 because it’s a negative number
8 0
3 years ago
Helppp please??? ill give most brainly
Sergeeva-Olga [200]

Answer:

46

Step-by-step explanation:

Since B is the midpoint of AC, the segments AB and BC must have equal length. This means that x + 13 = 2x + 3. Solving this, we see that x = 10. By substituting 10 for x, we see that the length of AB is 23, so the length of AC is 2*23, which is 46.

5 0
3 years ago
Read 2 more answers
a) What is an alternating series? An alternating series is a whose terms are__________ . (b) Under what conditions does an alter
andriy [413]

Answer:

a) An alternating series is a whose terms are alternately positive and negative

b) An alternating series \sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n where bn = |an|, converges if 0< b_{n+1} \leq b_n for all n, and \lim_{n \to \infty} b_n = 0

c) The error involved in using the partial sum sn as an approximation to the total sum s is the remainder Rn = s − sn and the size of the error is bn + 1

Step-by-step explanation:

<em>Part a</em>

An Alternating series is an infinite series given on these three possible general forms given by:

\sum_{n=0}^{\infty} (-1)^{n} b_n

\sum_{n=0}^{\infty} (-1)^{n+1} b_n

\sum_{n=0}^{\infty} (-1)^{n-1} b_n

For all a_n >0, \forall n

The initial counter can be n=0 or n =1. Based on the pattern of the series the signs of the general terms alternately positive and negative.

<em>Part b</em>

An alternating series \sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n where bn = |an|  converges if 0< b_{n+1} \leq b_n for all n and \lim_{n \to \infty} b_n =0

Is necessary that limit when n tends to infinity for the nth term of bn converges to 0, because this is one of two conditions in order to an alternate series converges, the two conditions are given by the following theorem:

<em>Theorem (Alternating series test)</em>

If a sequence of positive terms {bn} is monotonically decreasing and

<em>\lim_{n \to \infty} b_n = 0<em>, then the alternating series \sum (-1)^{n-1} b_n converges if:</em></em>

<em>i) 0 \leq b_{n+1} \leq b_n \forall n</em>

<em>ii) \lim_{n \to \infty} b_n = 0</em>

then <em>\sum_{n=1}^{\infty}(-1)^{n-1} b_n  converges</em>

<em>Proof</em>

For this proof we just need to consider the sum for a subsequence of even partial sums. We will see that the subsequence is monotonically increasing. And by the monotonic sequence theorem the limit for this subsquence when we approach to infinity is a defined term, let's say, s. So then the we have a bound and then

|s_n -s| < \epsilon for all n, and that implies that the series converges to a value, s.

And this complete the proof.

<em>Part c</em>

An important term is the partial sum of a series and that is defined as the sum of the first n terms in the series

By definition the Remainder of a Series is The difference between the nth partial sum and the sum of a series, on this form:

Rn = s - sn

Where s_n represent the partial sum for the series and s the total for the sum.

Is important to notice that the size of the error is at most b_{n+1} by the following theorem:

<em>Theorem (Alternating series sum estimation)</em>

<em>If  \sum (-1)^{n-1} b_n  is the sum of an alternating series that satisfies</em>

<em>i) 0 \leq b_{n+1} \leq b_n \forall n</em>

<em>ii) \lim_{n \to \infty} b_n = 0</em>

Then then \mid s - s_n \mid \leq b_{n+1}

<em>Proof</em>

In the proof of the alternating series test, and we analyze the subsequence, s we will notice that are monotonically decreasing. So then based on this the sequence of partial sums sn oscillates around s so that the sum s always lies between any  two consecutive partial sums sn and sn+1.

\mid{s -s_n} \mid \leq \mid{s_{n+1} -s_n}\mid = b_{n+1}

And this complete the proof.

5 0
3 years ago
Other questions:
  • Georgetown and Franklin are 9.7 in apart on a map that has a scale of 1.1 in : 15 mi. How far apart are the real cities?
    8·1 answer
  • A cashier has only one-dollar bills, quarters, and dimes. List more than 5 ways you could receive $2.50 in change
    8·1 answer
  • A Brainliest for the correct answer
    12·1 answer
  • 31 is 20% of what number
    7·2 answers
  • WHAT IS THE BENEFIT OF A "SPACE CUSHION" AROUND YOUR VEHICLE?
    15·1 answer
  • There are 32 students in a class . If the number of girls are 6 more than the numbers of boys, find the numbers​
    13·2 answers
  • What is the diamiter of 37.68
    7·1 answer
  • Come up with a rule for subtracting integers
    6·1 answer
  • Mr. Hamell had to pay an electrician to fix something in his home. He charged a service fee of $90 to come look at the problem,
    5·1 answer
  • Please help!!
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!