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3 years ago

Isopropanol major species present when dissolved in water

Chemistry

1 answer:

timofeeve [1]3 years ago

5 0

Answer : Isopropanol molecules ( C₃H₈O) are the major species present when dissolved in water.

Explanation :

Compounds are of 2 types.

1) Ionic compounds : These are formed by the transfer of electrons from a metal to a non metal.

When ionic compounds are dissolved in water, they get separated into ions.

Therefore the major species present in case of an ionic compound are ions.

2) Molecular (Covalent) compounds: These are formed by sharing of electrons among 2 or more non metals.

Covalent compounds are further categorized as

a) Polar covalent : Polar covalent compounds partially dissociate to form ions.

Therefore the major species in case of polar covalent compounds are the undissociated molecules and ions.

b) Non polar covalent : Non polar covalent compounds are unable to dissociate and they remain in molecular form when dissolved. So the major species in case of a non polar compound are undissociated molecules only.

Isopropanol is a non polar covalent compound. As discussed above it will have undissociated isopropanol molecules as major species.

Hence Isopropanol molecules ( C₃H₈O) are the major species present when dissolved in water.

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Read 2 more answers

What is the volume at STP of 3.44 x 1023 molecules of CO2

almond37 [142]

Answer:

C. 12.8 liters.

Explanation:

The Standard Temperature and Pressure (STP) of a gas are 273.15 K and 100 kilopascals. From Avogadro's Law, a mole of carbon dioxide contains $6.022 \times 10^{23}$ molecules. If we suppose that carbon dioxide behaves ideally, then the equation of state for ideal gas is:

$P\cdot V = n\cdot R_{u}\cdot T$ (1)

$P\cdot V = \frac{r\cdot R_{u}\cdot T}{N_{A}}$ (1b)

Where:

$P$ - Pressure, measured in pascals.

$V$ - Volume, measured in liters.

$r$ - Amount of molecules, no unit.

$N_{A}$ - Avogadro's number, no unit.

$R_{u}$ - Ideal gas constant, measured in pascal-liters per mole-Kelvin.

$T$ - Temperature, measured in Kelvin.

If we know that $P = 100000\,Pa$ , $r = 3.44\times 10^{23}$ , $N_{A} = 6.022\times 10^{23}$ , $T = 273.15\,K$ and $R_{u} = 8.314\times 10^{3}\,\frac{L\cdot Pa}{mol\cdot K}$ , then the volume of carbon dioxide at STP is:

$V = \frac{r\cdot R_{u}\cdot T}{N_{A}\cdot P}$

$V = \frac{(3.44\times 10^{23})\cdot \left(8.314\times 10^{3}\,\frac{L\cdot Pa}{mol\cdot K} \right)\cdot (273.15\,K)}{(6.022\times 10^{23})\cdot (100000\,Pa)}$

$V = 12.972\,L$

Therefore, the correct answer is C.

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3 years ago