The surface area of the large sphere is 128π cm²
<h3>Complete question</h3>
Two spheres have volumes of 8π cm3 and 64π cm3. If the surface area of the smaller sphere is 16π cm2, what is the surface area of the larger sphere?
<h3>How to determine the larger area?</h3>
The given parameters can be represented using the following ratio:
Small Area : Large Area = Small Volume : Large Volume
Substitute the given parameters
16π : Large Area = 8π : 64π
Express as fraction
Large/16π = 64π/8π
Multiply both sides by 16π
Large = 128π
Hence, the surface area of the large sphere is 128π cm²
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Answer:
C. 52
Step-by-step explanation:
First, find the base of the triangle. You can do this by looking at the top of the figure. 14 inches is the width of the rectangle, and 20 inches is the width of the rectangle and the base of the triangle. You can find the base of the triangle by subtracting.
The base of the triangle is 6. The height of the triangle is equal to the height of the rectangle, 8. Now you need to find the hypotenuse of the triangle using the Pythagorean theorem:
c is the hypotenuse. Find c:
The hypotenuse of the triangle is 10. Now that you know the hypotenuse, you can find the perimeter. Add all the sides:
The perimeter is 52 inches.
Answer:
90
Step-by-step explanation:
"how many one inch squares" is basically saying surface area. just find the area of each side and add them.
The answer is 4 because 2/3 times 6 ( flip 1/6 to multiply) equals 12/3 which equals 4
Answer:
The answer is C. 0.19 I hope this helped you good luck!