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I am Lyosha [343]
3 years ago
9

Determine if the side lengths form a right triangle. If not, is the longest side too long or too short ?

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
7 0

Answer:

Pythagorean theorem: a^2 + b^2 = c^2

14^2 + 48^2 = 50^2

2500 = 50^2

2500 = 2500, so this actually forms a right triangle.

Let me know if this helps!

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I need help, please im stuck on this problem
pashok25 [27]

Answer:

23cm

Step-by-step explanation:

When converting inches to centimeters the formula is in x 2.54, 9.2 x 2.54=23.368, 23cm!! Hope this helps!

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3 years ago
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PLEASE ANSWER + BRAINLIEST!!
lora16 [44]
I'd like to see some of your own efforts here.  This is the third time you've posted two "factor completelyl" problems, without sharing what you've already done.

<span>3v^2 - 8v - 16 cannot be reduced.  Thus, your best choice to find roots is to apply the quadratic formula:

         8 plus or minus sqrt( 64-4(3)(-16) )
v = ---------------------------------------------------
                                2(3)
        8 plus or minus sqrt( 64 + 192 ) 
   = ---------------------------------------------
                                 6
         8 plus or minus sqrt(256)
    = -------------------------------------
                             6

     = 8 + 16, all divided by 6, or    8 - 16, all divided by 6

     = 4 or -8/6, or 4 or -4/3.

The factors are (v-4) and (v + 4/3).</span>
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4 years ago
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Goshia [24]

30 since 80+70=150 180-150=30

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4 years ago
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Write the given equation of the line that passes through the given points <br>(4,0) and (0,2)​
kondaur [170]

Answer:

y= -1/2x + 2

or y = -0.5x + 2

Step-by-step explanation:

Use the slope formula to get the slope:

(y2-y1)/ (x2-x1)

(2-0)/(0-4)

2/-4

-1/2

Plug in any point in Point-Slope Formula:

y - y1 = m(x-x1)

y- 0 = -1/2 (x -4)

y = -x/2 + 4/2

y= -1/2x + 2

6 0
3 years ago
For f(x) = 2x + 1 and g(x) = x^2- 7, find (f - g)(x). ?
Irina18 [472]

Answer:

(f-g)(x)=-x^(2)+2x+8

the solutions are:

<em><u>x=4 or x=-2</u></em>

Step-by-step explanation:

(f-g)(x)=2x+1-(x^(2)-7)

(f-g)(x)=-x^(2)+2x+1+7

(f-g)(x)=-x^(2)+2x+8

does this help or should I solve for the zeros/solutions of this quadratic equation?

then:

-x^(2)+2x+8=0

-(x^(2)-2x-8)=0

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(x-4)(x+2)=0

<em><u>x=4 or x=-2</u></em>

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