Answer: The approximate perimeter is 19cm
Step-by-step explanation:
We know the positon of the 3 vertices of our triangle.
(i do not know if the first point is (0.6, 8) or (0, 6.8), i wil use the second one).
The vertices are:
(0, 6.8)
(4.5, 6.8)
(2.25, 0)
The perimeter of a triangle is equal to the sum of the length of the 3 sides.
To find the distance between two points (a,b) and (c,d) we must calculate:
D = √( (a - c)^2 + (b - d)^2)
Then the 3 distances that we have are:
(0, 6.8) to (4.5, 6.8)
D1 = √( (0 - 4.5)^2 + (6.8 - 6.8)^2) = 4.5 cm
(0, 6.8) to (2.25, 0)
D2 = √( (0 - 2.25)^2 + (6.8 - 0)^2) = 7.02 cm
(2.25, 0) to (4.5, 6.8)
D3 = √( (2.25 - 4.5)^2 + (0 - 6.8)^2) = 7.02 cm
Then the perimeter, rounding to the nearest cm is:
7.02 cm + 7.02cm + 4.5 cm = 18.54cm
Now, as the first number after the decimal point is a 5, we should round up.
The approximate perimeter is 19cm
