Answer:
min: -10
max: 18
minmax
Step-by-step explanation:
The three vertices of △ABC are in quadrant I. If △ABC is reflected in the x-axis, its image will lie in quadrant IV
Hope it helps
Explanation:
There may be a more direct way to do this, but here's one way. We make no claim that the statements used here are on your menu of statements.
<u>Statement</u> . . . . <u>Reason</u>
2. ∆ADB, ∆ACB are isosceles . . . . definition of isosceles triangle
3. AD ≅ BD
and ∠CAE ≅ ∠CBE . . . . definition of isosceles triangle
4. ∠CAE = ∠CAD +∠DAE
and ∠CBE = ∠CBD +∠DBE . . . . angle addition postulate
5. ∠CAD +∠DAE ≅ ∠CBD +∠DBE . . . . substitution property of equality
6. ∠CAD +∠DAE ≅ ∠CBD +∠DAE . . . . substitution property of equality
7. ∠CAD ≅ ∠CBD . . . . subtraction property of equality
8. ∆CAD ≅ ∆CBD . . . . SAS congruence postulate
9. ∠ACD ≅ ∠BCD . . . . CPCTC
10. DC bisects ∠ACB . . . . definition of angle bisector
Answer:
see explanation
Step-by-step explanation:
1 revolution is equivalent to the circumference of the wheel
1 revolution = πd ( d is the diameter )
= 70π cm
50 revolutions = 70π × 50 = 3500π cm = 35π m ≈ 110m ( nearest metre )
9514 1404 393
Answer:
- 33.0 m
- 26.1 mi
- 28.0 mi
- 33.0 mi
Step-by-step explanation:
In each of these Law of Sines problems, you are given side a and angles B and C and asked for side c (problems 1, 3, 4) or side b (problem 2). The solution is basically the same for each:
Find the missing angle. Find the side from ...
c = a·sin(C)/sin(A)
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1. angle A = 180°-89°-58° = 33°
c = (18 m)sin(89°)/sin(33°) ≈ 33.0 m
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2. angle C = 180°-13°-17° = 150°
b = (58 mi)sin(13°)/sin(150°) ≈ 26.1 mi
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3. angle A = 180°-61°-89° = 30°
c = (16 mi)sin(61°)/sin(30°) = 28.0 mi
__
4. angle A = 180°-39°-127° = 14°
c = (10 mi)sin(127°)/sin(14°) ≈ 33.0 mi
