Answer:
A
Step-by-step explanation:
Assuming the triangle is right, use Pythagoras' identity to find N
The square on the hypotenuse is equat to the sum of the squares on the other 2 sides.
Here the hypotenuse = 73, thus
N² + 48² = 73², that is
N² + 2304 = 5329 ( subtract 2304 from both sides )
N² = 3025 ( take the square root of both sides )
N = 
= 55 → A
It is B SAS. Let me know if you want and explanation
The equation for a sequence is
an=a1+(n-1)d
Replace the variable with what you were given you get
37=-13+(n-1)5
Simplify
37=-13+5n-5
Combine like terms
37=5n-18
Reverse operations
55=5n
Simplify
n=11
If from 0 - 10 there is 1 number ending in 3 (3) we'll aplly the same logic to 500.
Between 0-10 there is 3. Between 10 - 20 there is 13. Between 20-30 there is 23. Between 30-40 there is 33, etc.
If we divide 500 into 10 we get 50:
500 / 10 = 50
That means there are 50 groups of 10 in the number 500. If we know that every 10 numbers has 1 ending in 3, we multiply 1 by 50:
1 x 50 = 50
So, our conclusion is, that there are 50 numbers ending in 3 between 10 and 500.
Hope it helped,
BioTeacher101
