Answer:
When this runs you would get for each trial:
Child 1: X + (X or Y)
Child 2: X + (X or Y)
Child 3: X + (X or Y)
Child 4: X + (X or Y)
Child 5: X + (X or Y)
Step-by-step explanation:
Well in this scenario we would be looking to see if the gender of the 5 children is going to be a girl or boy. Depending on the situation there is a 50/50 chance you get a XY or XX combinations which determine the gender.
So if the couple plans to have 5 children we would run a simulation that would randomly generate either a X or Y and add it to an X for 5 children. This would be done 120 times to get the desired amount of trials.
Each (X or Y) would be a 50/50 chance probability meaning 1/2 chance to get X and another 1/2 to get Y.
Well I’ll just make my own table
Key/legend: when y = 0 x = -2
X=|-3 |-2 | -1| 0|1 |2|3 |4 |5 |
Y=|17 |-12|-7|-2|3|8|13|18|23|
Answer: Coordinates C and D
Step-by-step explanation:
(i) Use law of cosine:
c² = a² + b² − 2ab cos C
c² = (√3 − 1)² + (√3 + 1)² − 2(√3 − 1)(√3 + 1) cos 60°
c² = 3 − 2√3 + 1 + 3 + 2√3 + 1 − 2(3 − 1) (½)
c² = 6
c = √6
(ii) Use law of sines:
a / sin A = c / sin C
(√3 − 1) / sin A = √6 / (½√3)
(√3 − 1) / sin A = 2√2
½ (√3 − 1) = √2 sin A
½ (√6 − √2) = 2 sin A
¼ (√6 − √2) = sin A
Use a calculator:
A = 15°
(iii) Use SAS area:
A = ½ ab sin C
A = ½ (√3 − 1) (√3 + 1) sin 60°
A = ½ (3 − 1) (½√3)
A = ½√3
