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Olegator [25]
3 years ago
10

-nunTHE SUM OF THREE TIMES ANumbers and 11​

Mathematics
1 answer:
Vikentia [17]3 years ago
8 0

Answer:

3x + 11

Step-by-step explanation:

Remember BPEMDAS.

"Three times a number" is saying multiply 3 times a variable; in this case, <em>x</em>. So we have 3x

"The sun of 3x and 11" is saying add our 3x and 11, so: 3x + 11

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What is Y equals 7x plus 3
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2 years ago
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Answer:

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Step-by-step explanation:

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4 0
1 year ago
Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio
Galina-37 [17]

Answer:

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is (x_1,y_1)=(-3, 2)

Equation of a circle with center (h,k) and radius 'r' is given as:

(x-h)^2+(y-k)^2=r^2

Here, (h,k)=(5,-4)

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

r^2=(h-x_1)^2+(k-y_1)^2

Using distance formula for the points (5, -4) and (-3, 2), we get

r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100

Therefore, the equation of the circle is:

(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100

Now, rewriting it in the form asked in the question, we get

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

4 0
3 years ago
Pls help me it's due today​
Dimas [21]

Answer:

r³ + 15r² - 10r - 4

Step-by-step explanation:

First, note you can remove the brackets, in this case they contribute nothing at all.

Then, group the like terms and add them, e.g., we have 3r³ and -2r², they add up to r³.

Finally, order them from greatest power of r to smallest power of r.

That's all!

8 0
3 years ago
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