The answer is x = -19
Solution:
9(x + 1) = -162
Expand:
9x + 9 = -162
9x = -162 - 9
9x = -171
x = -171/9
x = -19
If it’s in slope intercept I pretty sure the slope should be 5 because if y=mx+b and the m is slope then slope should be 5
Answer:
Step-by-step explanation:
- By using trigonometric ratios
The new function is g(x) =-1(1/-x) +2.
The transformation of function f(x) to function g(x) is given by g(x)=A f(Bx+ H)+K. where the constant A scales the function vertically. (A negative A reflects the function about the x-axis B scales the function horizontally. (A negative B reflects the function on the y-axis.) H shifts the function horizontally, and K shifts the function vertically.
Convert f(x) to g(x)
where the conversion is g(x)=f(x)+2.
A perpendicular line has negative reciprocal slopes, so for g(x) to be perpendicular to f(x), we need to get the negative reciprocal of -x, which is -1(1/-x)
So, f(x)=-x-2 ; m = -1
From the above information, we get g(x) as follows.
g(x) =-1(1/-x) +2
More problems related to finding new functions for a given function are below.
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Answer:
and 
Step-by-step explanation:
The equation of curve is
We need to find the equation of the tangent line to the curve at the point (-3, 1).
Differentiate with respect to x.
![2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})](https://tex.z-dn.net/?f=2%5B2%28x%5E2%2By%5E2%29%5Cfrac%7Bd%7D%7Bdx%7D%28x%5E2%2By%5E2%29%5D%3D25%282x-2y%5Cfrac%7Bdy%7D%7Bdx%7D%29)
The point of tangency is (-3,1). It means the slope of tangent is 
.
Substitute x=-3 and y=1 in the above equation.
Divide both sides by 130.
If a line passes through a points 
with slope m, then the point slope form of the line is
The slope of tangent line is 
and it passes through the point (-3,1). So, the equation of tangent is
Add 1 on both sides.
Therefore, and .
