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3 years ago

14

Anna has to read the lightning theif for class. Anna reads 30 chapters in 20 days. Emma reads BLANK chapters in 24 days. what is

the unknown rate?

1 answer:

olasank [31]3 years ago

3 0

32.5

Anna reads 30 in 20 days which means she read 15 chapters in 10 days and di ide 10 by 4 and it 2.5 and add that to 30 and you have your answer

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What is the graph of the solution to the following compound inequality?

ohaa [14]

Answer:

<h2>C.</h2>

Step-by-step explanation:

<, > - open circle

≤, ≥ - solid circle

<, ≤ - draw to the left

>, ≥ - draw to the right

$3-x\geq2\qquad\text{subtract 3 from both sides}\\\\-x\geq-1\qquad\text{change the signs}\\\\\boxed{x\leq1}\\\\4x+2\geq10\qquad\text{subtract 2 from both sides}\\\\4x\geq8\qquad\text{divide both sides by 4}\\\\\boxed{x\geq2}$

3 0

3 years ago

The volume of a sphere is two-thirds of a cylinder. What is the volume of a cylinder that has the same diameter as a sphere with

sattari [20]

Answer:

$V_2= \frac{28}{3} u^3$

Step-by-step explanation:

Given

Represent the volume of the cylinder with V1 and the volume of the sphere with V2

So, from the first statement: we have:

$V_2 =\frac{2}{3}V_1$

and

$V_1 = 14u^3$

To solve for $V_2$ , we simply substitute $14u^3$ for $V_1$ in $V_2 =\frac{2}{3}V_1$

$V_2 =\frac{2}{3}V_1$

$V_2= \frac{2}{3} * 14u^3$

$V_2= \frac{2* 14}{3} u^3$

$V_2= \frac{28}{3} u^3$

Hence, the volume of the sphere is $\frac{28}{3} u^3$

5 0

2 years ago

Help i dont know the answer

zhenek [66]

Answer:

25

Step-by-step explanation:

In her first 5 days, she reads 80 pages. That means that per day, she reads 16 pages. Then, she had 400 pages left, since 480-80 = 400.

So, you divide 400/16 = 25 days.

7 0

3 years ago

Read 2 more answers

Help plz find the equation

tatiyna

Question # 1

Step-by-step Explanation:

Given

$\frac{1}{2}\div \frac{2}{3}$

solving

$\frac{1}{2}\div \frac{2}{3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{1}{2}\times \frac{3}{2}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{1\times \:3}{2\times \:2}$

$\mathrm{Multiply\:the\:numbers:}\:1\times \:3=3$

$=\frac{3}{2\times \:2}$

$\mathrm{Multiply\:the\:numbers:}\:2\times \:2=4$

$=\frac{3}{4}$

Therefore, completing the blanks:

$\frac{1}{2}\div \frac{2}{3}=\frac{1}{2}\times \frac{3}{2}=\frac{3}{4}$

Question # 3

Step-by-step Explanation:

Given

$\frac{2}{5}\div \frac{3}{4}$

solving

$\frac{2}{5}\div \frac{3}{4}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{2}{5}\times \frac{4}{3}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{2\times \:4}{5\times \:3}$

$\mathrm{Multiply\:the\:numbers:}\:2\times \:4=8$

$=\frac{8}{5\times \:3}$

$\mathrm{Multiply\:the\:numbers:}\:5\times \:3=15$

$=\frac{8}{15}$

Therefore, completing the blanks:

$\frac{2}{5}\div \frac{3}{4}=\frac{2}{5}\times \:\frac{4}{3}=\frac{8}{15}$

Question # 5

Step-by-step Explanation:

Given

$\frac{3}{4}\div \frac{5}{7}$

solving

$\frac{3}{4}\div \frac{5}{7}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{3}{4}\times \frac{7}{5}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{3\times \:7}{4\times \:5}$

$\mathrm{Multiply\:the\:numbers:}\:3\times \:7=21$

$=\frac{21}{4\times \:5}$

$\mathrm{Multiply\:the\:numbers:}\:4\times \:5=20$

$=\frac{21}{20}$

Therefore, completing the blanks:

$\frac{3}{4}\div \frac{5}{7}=\frac{3}{4}\times \:\frac{7}{5}=\frac{21}{20}$

6 0

3 years ago

when the expression: 4x^4 + 24x^3 + 12x^3 + 8x is factored completely, what is the largest factor that can be factored out?

Fofino [41]

Let's start by grouping like terms so we can factor out the most
(4x^4+24x^3)+(12x^2+8x)
now let's factor out as much as possible. we see all coefficients are multiples of 4, we will also factor out as high a degree of x as we can
4x^3(x+6)+4x(3x+2)
now we see that we still have a common multiple of 4x that we can remove
4x(x^2(x+6)+(3x+2))
so we find 4x is the largest value we can factor out

5 0

3 years ago

Read 2 more answers