The extinct animal is most similar to the bottom left due to the spinal similarities. The spine does not demonstrate a sigmoidal curve like the bottom right does. Answer would be bottom left.
Chroloplasts---it is important for a plant cell to have a chloroplast in order to create glucose.
Answer:
1/4 suffer from hemophilia
1/4 are heterozygous
Explanation:
So since they are normal but their son isn't it is assumed that the mom is the carrier since the dad has to be X^HY
X^HY x X^HX^h
Set up a pedigree
X^HX^H X^HX^h
X^HY X^hY
1/4 suffer from hemophilia (X^h)
1/4 are heterozygous (X^HX^h)
Answer:
a) How many genotypes will occur in F2
--The genotypes would be- AA Aa aa BB Bb bb CC Cc cc DD Dd dd EE Ee ee (15 genotypes)
Reason-
This is because, after crossing the parents, the F1 generation would all be Heterozygous dominant since one parent is homozygous dominant, while the other is homozygous recessive.
b) 25% of all F2 genotypes would be recessive across the 5 loci
Reason-
This is because each loci would produce only a 25% chance for a recessive trait, which would results to a general probability of 25% also.
c) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aaBBccDDEE
d) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aabbccddEE
Answer:
mala maff Kar ra meko angraze nahi ati rae baba
