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kow [346]
2 years ago
5

Identify the correct ordered pairs made using the corresponding terms of these two sequences, with Sequence 1 terms first. Seque

nce 1: 3, 5, 7, 9, 11…. Sequence 2: 5, 7, 9, 11, 13…
(3, 5), (5, 9), (7, 11), (9, 7), (11, 13)
(3, 5), (5, 11), (7, 9), (9, 7), (11, 13)
(5, 3), (7, 5), (9, 7), (11, 9), (13, 11)
(3, 5), (5, 7), (7, 9), (9, 11), (11, 13)
Mathematics
2 answers:
Artist 52 [7]2 years ago
8 0

Answer:

sorry i cant

Step-by-step explanation:

BUT im doing a winter event of 2 easy questions 50 pts and brainliest each

allsm [11]2 years ago
6 0

Answer:

Ur answer is D. (3, 5), (5, 7), (7, 9), (9, 11), (11, 13)

Step-by-step explanation:

Hope this helps

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PLEASE HELPP! Question 1: Factorise each of the following (a) x² + 7x + 12 (b) x² + 6x + 8 (c) x² + 5x + 6 (d) x² + 8x + 7
Liula [17]

Answer:

<em><u>Using the mid-term break formula for all of them.</u></em>

a) x²+7x+12

= x²+3x+4x+12

= x(x+3)+4(x+3)

= (x+4)(x+3)

b) x²+6x+8

= x²+2x+4x+8

= x(x+2)+4(x+2)

= (x+4)(x+2)

c) x²+5x+6

= x²+2x+3x+6

= x(x+2)+3(x+2)

= (x=3)(x+2)

d) x²+8x+7

= x²+7x+x+7

= x(x+7)+1(x+7)

= (x+1)(x+7)

6 0
4 years ago
Read 2 more answers
7
trasher [3.6K]

Answer:

we have to use the formula of simple interest, which is

I = P r t

Where I is the interest earned, P is the amount invested, r is the rate of interest and t is the time duration .

In the given question, I = $4840 , r =11% or 0.11, t=11, P is unknown .

Substituting the values in the formula, we will get

4840=0.11*11*P4840=0.11∗11∗P

4840=1.21 P4840=1.21P

P=4000

So she invested $4000

5 0
2 years ago
Read 2 more answers
Solve the expression for a=12 , b=6 and c=3
iragen [17]

Answer:

12(6^2-6x3)= 216

3^2 = 9

Step-by-step explanation:

216/9 = 24

7 0
4 years ago
Of 580580 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compa
Lubov Fominskaja [6]

Answer:

a) The 99% confidence interval would be given (0.204;0.296).

b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation  

n=580 represent the random sample taken    

X represent the seafood sold in the country that is mislabeled or misidentified by the people

\hat p=0.25 estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

\alpha=0.01 represent the significance level (no given, but is assumed)    

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.25 - 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.204

0.25 + 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.296

And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

Part c

A government spokesperson claimed that the sample size was too​ small, relative to the billions of pieces of seafood sold each​ year, to generalize. Is this criticism​ valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

4 0
4 years ago
Small library contains 700 novels. how many ways can You check out three novels
schepotkina [342]

The first book you select can be any one of 700.

. . . For each of those ...

The second book can be any one of the other 699.

. . . For each of those ...

The third book can be any one of the remining 698.

The total number of ways to gather three books from the shelves into your hands is  (700 · 699 · 698)  =  <em>341,531,400 ways</em> .

<em>BUT ...</em>

When you bring three books to the check-out counter, Marian the Librarian doesn't know in which order you took them down off the shelves.  You could have gathered the same three books in (3 · 2 · 1) = 6 different ways.

So, even though there are 341,531,400 ways to<em> </em>gather up three books, there are only (341,531,400 / 6) = 56,921,900 different GROUPS of three books that you can choose to take home.

8 0
4 years ago
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