The bearing of Q from P is 150° and the bearing of P from R is 15°.if Q and R are 244metres and 324metres respectively from P.(i
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Answer:
Step-by-step explanation:
The distance (d) between two points in 3 dimensions is ...
d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)
Then the distance between (a, -b, -4) and (0, 0, 0) is ...
d = √((a -0)² +(-b -0)² +(-4 -0)²)
= √(a² +b² +16)