Answer:
Step-by-step explanation: the thing is that if kelvin walks 5km south and then 8 km east the displacement is that he won’t really make it to the east.
Answer:
Step-by-step explanation:
I have the same question and I'm looking for the answer
If inspection department wants to estimate the mean amount with 95% confidence level with standard deviation 0.05 then it needed a sample size of 97.
Given 95% confidence level, standard deviation=0.05.
We know that margin of error is the range of values below and above the sample statistic in a confidence interval.
We assume that the values follow normal distribution. Normal distribution is a probability that is symmetric about the mean showing the data near the mean are more frequent in occurence than data far from mean.
We know that margin of error for a confidence interval is given by:
Me=
α=1-0.95=0.05
α/2=0.025
z with α/2=1.96 (using normal distribution table)
Solving for n using formula of margin of error.

n=
=96.4
By rounding off we will get 97.
Hence the sample size required will be 97.
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The given question is incomplete and the full question is as under:
If the inspection division of a county weights and measures department wants to estimate the mean amount of soft drink fill in 2 liters bottles to within (0.01 liter with 95% confidence and also assumes that standard deviation is 0.05 liter. What is the sample size needed?
Answer:
The area of the walls is 
Step-by-step explanation:
we know that
The area of the walls is equal to the perimeter of the conference room multiplied by the height of the ceiling
so
=2,160\ ft^{2}](https://tex.z-dn.net/?f=A%3D2%5B40%2B50%5D%2812%29%3D2%2C160%5C%20ft%5E%7B2%7D)
Step-by-step explanation:
101° = (6x + 5)° (by F angles)
Therefore 6x = 96 and x = 16.