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Tatiana [17]
2 years ago
10

Redondear a 4 decimales 35614326​

Mathematics
1 answer:
Verizon [17]2 years ago
4 0
Can you translate i can help you better
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The coordinate grid above shows a pentagon. The pentagon is translated 1 unit to the left and 10 units down to create a new pent
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The pentagon is translated 1 unit to the left, so the points move to the left by 1 unit. Moving left or right changes the x value, when you move right, the x value increases, when you move left, x decreases. Since x is going left 1 unit:

So x - 1

10 units down. Moving up down or up changes the y value, when you move down, y decreases, when you move up, y increases. Since the pentagon is going down 10 units:

y - 10

Your answer is A

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2 years ago
Find the distance between 2-4i and d 6+i
nlexa [21]

How do you find the distance between two complex numbers?

For two points in the complex plane, the distance between the points is the modulus of the difference of the two complex numbers. (s − a)+(t − b)i = (s − a)2 + (t − b)2. So, d = (s − a)2 + (t − b)2 is the difference between the two points in the complex plane.

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3 years ago
What produces a graph in a straight line
Blababa [14]
Linear equations in one variables shows always graph in straight line,

For ex: x = 3, y = 4, x = -1.5, y = -2/3

Also two variables linear equations with degree of 0 or 1 (Each term) shows always graph in straight line,

For ex: x + y = 5, 2x - 4y = 7 etc.
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What is 9+10 *hint its a vine*
nika2105 [10]

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6 0
3 years ago
Read 2 more answers
Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity. In the given triangle ABC, angle A
lana66690 [7]

The relationship between the lengths of the sides of a right triangle are

given by Pythagoras theorem.

  • Part A: <u>ΔABC is similar to ΔADC</u>
  • Part B: ΔABC and ΔADC are similar according <u>AA similarity postulate</u>
  • Part C: <u>DA = 6</u>

Reasons:

Part A:

∠A = 90°

Segment AD ⊥ Segment BC

Location of point D = Side BC

Part A: In triangle ΔABC, we have;

∠A = 90°, ∠B = 90° - ∠C

In triangle ΔADC, we have;

∠ADC = 90°, ∠DAC = 90° - ∠C

∴ <u>ΔABC is similar to ΔADC</u> by Angle-Angle, AA, Similarity Postulate

Part B: The triangles are similar according to <u>AA similarity postulate</u>,

because two angles in one triangle are equal to two angles in the other

triangle and therefore, by subtraction property of equality, the third angle

in both triangles are also equal.

Part C: The length of DB = 9

The length of DC = 4

Required: Length of segment DA

In triangle ΔABD, we have;

∠BDA = 90°= ∠ADC

∠DAC ≅ ∠B by Congruent Parts of Congruent Triangles are Congruent

Therefore;

ΔABD ~ ΔADC by AA similarity, which gives;

\displaystyle \frac{\overline{DA}}{\overline{DC}}  = \frac{\overline{BD}}{\overline{DA}}

\overline{DA}^2 = \overline{DC} \times \overline{BD}

Which gives;

\overline{DA}^2 = 4 × 9 = 36

\overline{DA} = √(36) = 6

\overline{DA}<u> = 6</u>

Learn more here:

brainly.com/question/2269451

3 0
2 years ago
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