Let X represent the SAT score of an entering freshman at University X. The random variable X is shown to have a N(1200, 90) dist
ribution. Let Y represent the SAT score of an entering freshman at University Y. The random variable Y is know to have N(1215, 110) distribution. A random sample of 100 freshman is obtained form each university. Let X bar = the sample mean of the 100 scores from university X and Y bar = the sample mean of the 100 scores from University Y. What is the probability that X bar will be greater than Y bar?
The correct answer to this question is 0.1456. This is <span>the probability that X bar will be greater than Y bar. </span>Probability is the measure of how likely an event is. The formula is the ratio of the number of favorable outcomes to the total number of possible outcomes. Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.
If you would like to know how many hours will Lena need to work before she can afford to buy the computer, you can calculate this using the following steps:
$900 - $473 = $427
$427 / $7 = 61 hours of yard work
Result: Lena will need to work 61 hours before she can afford to buy the computer.
