Hello,
-5x-15>10+20x
==>-15-10>20x+5x
==>-25>25x
==>-1>x
==>x<-1
If the store decreases its prices by 20%, then ur actually paying 80%
0.80(120) <=== ur expression
lets check..
0.80(120) = 96
120 - 0.2(120) = 120 - 24 = 96 (yep, it matches)
Answer: Choice D)
F(x) > 0 over the inverval (-infinity, -4)
Translation: The y or f(x) values are positive whenever x < -4.
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Further Explanation:
Recall that y = f(x), so if we say something like f(x) < 0 then we mean y < 0. Choice A is false because points on the curve to the left of x = -4 have positive y coordinates. Similar reasoning applies to choice B as well.
Choice C is false because while the interval (-infinity, -4) is above the x axis, the portion from x = -4 to x = -3 is below the x axis.
Choice D is true because everything to the left of x = -4 is above the x axis. Pick any point on the blue curve that is to the left of x = -4. This point will be above the horizontal x axis. Keep in mind that the parenthesis notation attached to the -4 means we dont include -4 as part of the interval.
The two equations that could be used to determine the number of pictures (x) and songs (y) is x + y = 16 and 650x + 2200y = 18150
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
Let x represent the number of pictures and y represent the number of songs, hence:
x + y = 16 (1)
And:
650x + 2200y = 18150 (2)
The two equations that could be used to determine the number of pictures (x) and songs (y) is x + y = 16 and 650x + 2200y = 18150
Find out more on equation at: brainly.com/question/2972832
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Answer:
ΔA'B'C' is congruent to ΔABC
Step-by-step explanation:
See attached for the construction of ΔA'B'C'. (The vertices are labeled ABC.)
We computed angle B to be ...
∠B = 180° -∠A -∠C
∠B = 180° -103° -57° = 20°
We constructed segment BC of length 6.5. Then we constructed angles of 20° and 57° from B and C, respectively. The location where the rays from those angles cross is point A', and the angle there is 103°, as required.
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ΔA'B'C' is congruent to ΔABC by the ASA congruence postulate.
