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Ulleksa [173]
3 years ago
11

Bicycle Inc. rents bikes for $11 plus $5 per hour. Maria paid $51 to rent a bike. For how many hours, h, did she rent the bike?

Mathematics
1 answer:
N76 [4]3 years ago
5 0

Answer:

She spent 8 hours with the bike. She did rent the bike.

Step-by-step explanation:

The $11 fee is only a one time payment. The $5 is every hour so 5x8 is 40+11 is 51.

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zysi [14]

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6 0
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Please help I will give brainliest
Monica [59]

Answer:

52, 60, 68, 76..

Step-by-step explanation:

8 0
3 years ago
What is the change that occurs to the parent function f(x) = x^2 given the function f(x) = 2(x + 2)^2 + 1.
nikitadnepr [17]

Answer:

The graph is stretched by a factor of 2, moves 2 units to the left, and 1 unit up.

Step-by-step explanation:

The base of the quadratic function is

f(x) =  {x}^{2}

We can transform this function to look narrower or wider.

Looking narrower is termed a stretch.

This happens when a>1

Looking wider is termed a compression.

This happens when 0<a<1

We can also

g(x) = a {(x   + h)}^{2}  + k

+h moves the parent graph to the left by h units

-h moves the parent graph to the left by h units.

+ k moves the parent function up by k units

- k moves the parent function down by k units.

The change that occurs to

f(x) =  {x}^{2}

given

f(x) = 2( {x  + 2)}^{2}  + 1

is that, the graph is stretched by a factor of 2, moves 2 units to the left, and 1 unit up

Therefore the last choice is the correct answer.

3 0
3 years ago
The equation y-2/3=(x-1/4) is written in point-slope from what equation in slope-intercept from
Maksim231197 [3]

Answer:

y=x+5/12

good luck...

3 0
3 years ago
Angle $eab$ is a right angle, and $be = 9$ units. what is the number of square units in the sum of the areas of the two squares
Alla [95]
Let the measure of side AB be x, then, the measue of side AE is given by

AE=\sqrt{9^2-x^2}.

Now, ABCD is a square of size x, thus the area of square ABCD is given by

Area=x^2

Also, AEFG is a square of size \sqrt{9^2-x^2}, thus, the area of square AEFG is given by

Area=\left(\sqrt{9^2-x^2}\right)^2=9^2-x^2=81-x^2

<span>The sum of the areas of the two squares ABCD and AEFG is given by

x^2+81-x^2=81

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>
8 0
3 years ago
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