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iragen [17]
3 years ago
8

Write the equation of the line in slope-intercept that has passes through the points (2,-5) and (8, 13). ​

Mathematics
1 answer:
const2013 [10]3 years ago
8 0

Answer:

The equation of the straight line in Slope- intercept form

 y = 3 x - 11

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given points are   (2,-5) and (8, 13)

The Slope of the line

            m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} } = \frac{13-(-5)}{8-2} = \frac{18}{6} =3

Equation of the line having slope 'm' and given point

        y - y_{1} = m (x - x_{1} )

(x₁ , y₁)   =    ( 2, -5 )  

        y - (-5) = 3 (x - 2 )

       y + 5 = 3x - 6

The equation of the straight line in slope intercept form

    y = m x + c

       y = 3 x - 6-5

       y = 3 x - 11

<u><em>Final answer:</em></u>-

The equation of the straight line in Slope- intercept form

 y = 3 x - 11

     

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Expand<br> (2x - 3)4 <br><br> Can you help me expand this by using the binomial theorem?
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The value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

<h3>How to expand the expression?</h3>

The expression is given as:

(2x -3)^4

Using the binomial expansion, we have:

(2x -3)^4 = ^4C_0 * (2x)^4 * (-3)^0 +^4C_1 * (2x)^3 * (-3)^1 + ^4C_2 * (2x)^2 * (-3)^2 + ^4C_3 * (2x)^1 * (-3)^3 + ^4C_4 * (2x)^0 * (-3)^4

Evaluate the combination factors.

So, we have:

(2x -3)^4 = 1 * (2x)^4 * (-3)^0 + 4 * (2x)^3 * (-3)^1 + 6 * (2x)^2 * (-3)^2 + 4 * (2x)^1 * (-3)^3 + 1 * (2x)^0 * (-3)^4

Evaluate the exponents and the products

(2x -3)^4 = 16x^4  + 96x^3  +216x^2 -216x + 81

Hence, the value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

Read more about binomial expansions at:

brainly.com/question/13602562

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